A Bullet Leaves A Rifle With A Muzzle Velocity Of 521 M/S

Question

A Bullet Leaves A Rifle With a Muzzle Velocity Of 521 Ms While Ac A bullet leaves a rifle with a muzzle velocity of 521 m/s. While accelerating through the barrel of the rifle, the bullet moves a distance of 0.840 m. Determine the acceleration of the bullet (assume a uniform acceleration). Ima Hurryin is approaching a stoplight moving with a velocity of +30.0 m/s. The light turns yellow, and Ima applies the brakes and skids to a stop. If Ima's acceleration is -8.00 m/s², then determine the displacement of the car during the skidding process. (Note that the direction of the velocity and the acceleration vectors are denoted by a + and a - sign.)

Dr. Jack HW Helper · Accepted Answer

A Bullet Leaves A Rifle With a Muzzle Velocity Of 521 Ms While Ac Introduction Physics problems involving motion often require understanding and applying fundamental kinematic equations. Two such applications include analyzing the acceleration of a projectile within a confined barrel and determining the displacement of a vehicle during braking. The first problem involves calculating the uniform acceleration of a bullet, while the second pertains to finding the distance traveled by a car decelerating under a constant negative acceleration. Problem 1: Bullet acceleration within the rifle barrel The problem states that a bullet exits a rifle with a muzzle velocity of 521 m/s, having traveled through the barrel a distance of 0.840 m under uniform acceleration. The goal is to find the acceleration of the bullet during this phase. Designating known quantities: - Final velocity, $ v = 521\, \text{m/s} $ - Distance traveled in the barrel, $ s = 0.840\, \text{m} $ - Initial velocity, $ u = 0\, \text{m/s} $ (assuming the bullet starts at rest within the barrel) The kinematic equation suitable here is: $$ v^2 = u^2 + 2as $$ Rearranged to solve for acceleration $ a $: $$ a = \frac{v^2 - u^2}{2s} $$ Calculating acceleration: $$ a = \frac{(521)^2 - 0}{2 \times 0.840} = \frac{271441}{1.68} \approx 161677.98\, \text{m/s}^2 $$ Thus, the bullet experiences an approximate acceleration of 161,678 m/s² within the rifle barrel, which is consistent with rapid projectile acceleration performed by firearms. Problem 2: Displacement during vehicle braking Ima Hurryin approaches a stoplight at a velocity of $ +30.0\, \text{m/s} $. The vehicle’s acceleration when braking is $ -8.00\, \text{m/s}^2 $. The objective is to determine the displacement during the braking process. Known quantities: - Initial velocity, $ u = +30.0\, \text{m/s} $ - Final velocity, $ v = 0\, \text{m/s} $ - Acceleration, $ a = -8.00\, \text{m/s}^2 $ Using the kinematic equation: $$ v^2 = u^2 + 2a s $$ whi

A Bullet Leaves A Rifle With A Muzzle Velocity Of 521 M/S

A Bullet Leaves A Rifle With a Muzzle Velocity Of 521 Ms While Ac

Paper For Above instruction

Introduction

Problem 1: Bullet acceleration within the rifle barrel

Problem 2: Displacement during vehicle braking

Discussion

Conclusion

References