A Company Has Been Assigned A Class B Address Subnet Of This

A Company Has Been Assigned Aclass Baddress A Subnet Of This Company

A company has been assigned a class B address. A subnet of this company has network address 177.82.162.32 and direct broadcast address 177.82.190.63. a) Based on the previous information, provide the two smallest network addresses that can be assigned to a subnet of this company. b) Provide the smallest and largest IP address that can be assigned to a host of each subnets of question “a)”. c) Provide the two largest network address that can be assigned to a subnet of this company. d) Provide the smallest and largest IP address that can be assigned to a host of each subnet of previous question “c)”. You must provide the values of all derived network addresses and IP addresses in Dotted Decimal Notation. You must show your derivations.

Paper For Above instruction

This paper explores the subnetting of a Class B network assigned to a company, based on the provided network address and broadcast address. The goal is to identify the smallest and largest network addresses for subnets, as well as the range of host addresses within those subnets. The analysis involves calculating network and broadcast addresses, determining subnet masks, and deriving the address ranges for hosts within the subnets.

Understanding the Given Data

The network address is 177.82.162.32, and the broadcast address is 177.82.190.63. Both are within the same Class B network, where the default subnet mask is 255.255.0.0. However, since specific subnet information is provided, it indicates subnetting has been implemented, dividing the Class B address space into smaller subnets.

Class B addresses range from 128.0.0.0 to 191.255.255.255, with a default subnet mask of 255.255.0.0. This IP range supports up to 65,536 addresses. The given network address (177.82.162.32) falls within this class, and the subnetting process involves creating smaller network segments.

Deriving the Subnet Mask and Address Range

The significant clues are the network address and broadcast address:

- Network address: 177.82.162.32

- Broadcast address: 177.82.190.63

Expressed in binary, these addresses help determine the subnet mask, which defines how the network is partitioned.

First, convert the addresses into binary:

- 177.82.162.32: 10110001.01010010.10100010.00100000

- 177.82.190.63: 10110001.01010010.10111110.00111111

Looking at the third octet:

- 162 in binary: 10100010

- 190 in binary: 10111110

Between 162 and 190, the bits changing are in the lower bits of the third octet, indicating subnetting within the third octet.

Calculating the subnet mask:

The range from 162 to 190 in the third octet suggests that the subnet mask extends into the third octet. The difference is 190 - 162 + 1 = 29 addresses in the subnet.

This points to a subnet mask of 255.255.224.0, which corresponds to /19 prefix:

- 255.255.224.0 in binary:

255: 11111111

255: 11111111

224: 11100000

0: 00000000

This /19 mask allows for 2^13 addresses per subnet (8192 total), with block size of 32 in the third octet.

Checking the subnet boundaries:

- Network addresses are assigned with increments of 32 in the third octet.

Calculating subnet addresses:

- First subnet: 177.82.160.0 to 177.82.191.255 (but constrained by our addresses)

Given our specific network address (177.82.162.32) and broadcast address (177.82.190.63), the subnet ranges approximately from:

- Network address: 177.82.160.0

- Broadcast address: 177.82.191.255

But our subnet of interest is between specific addresses:

- Network address: 177.82.162.32

- Broadcast address: 177.82.190.63

Now, to find the smallest network addresses for subnets, we look at the subnet boundaries, which are aligned with the subnet mask.

a) Two Smallest Network Addresses for Subnets

Since subnetting partitions the network with blocks of 32 in the third octet:

- The first subnet: 177.82.160.0

- The second subnet: 177.82.192.0

Given the current subnet is 177.82.162.32 to 177.82.190.63, these are within the 177.82.160.0/19 subnet.

Therefore, the smallest network addresses for the subnets are:

1. 177.82.160.0

2. 177.82.192.0

b) Smallest and Largest IP Addresses for Hosts in Each Subnet

For each of these subnets, the usable host IP addresses range from:

- Smallest host IP: network address + 1

- Largest host IP: broadcast address - 1

In the 177.82.160.0/19 subnet:

- Network address: 177.82.160.0

- Broadcast address: 177.82.191.255

Hosts range from 177.82.160.1 to 177.82.191.254

Similarly, in the 177.82.192.0/19 subnet:

- Network address: 177.82.192.0

- Broadcast address: 177.82.223.255

Hosts range from 177.82.192.1 to 177.82.223.254

c) Two Largest Network Addresses for Subnets

In this context, the largest network addresses are the subnet addresses with the highest third octet values within the Class B address space, which are:

1. 177.82.224.0

2. 177.82.255.0

These correspond to larger subnet blocks beyond the initial subnets.

d) Smallest and Largest IP Addresses for Hosts in These Largest Subnets

For 177.82.224.0/19:

- Hosts range: 177.82.224.1 to 177.82.255.254

For 177.82.255.0/19:

- Hosts range: 177.82.255.1 to 177.82.255.254

Conclusion

The subnetting analysis based on the provided network and broadcast addresses reveals the subnet masks and address ranges. The smallest subnets are 177.82.160.0/19 and 177.82.192.0/19, while the largest subnets include 177.82.224.0/19 and 177.82.255.0/19, with corresponding host address ranges derived from their network and broadcast addresses.

References

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