Automatic Filling Machine For 1-Liter Bottles
An Automatic Filling Machine Is Used To Fill 1 Liter Bottles Of Cola
An automatic filling machine is used to fill 1-liter bottles of cola. The machine’s output is approximately normal with a mean of 0.99 liter and a standard deviation of 0.05 liter. Output is monitored using means of samples of 26 observations. Use Table-A. a. Determine upper and lower control limits that will include roughly 97 percent of the sample means when the process is in control. (Do not round intermediate calculations. Round your answers to 4 decimal places.)
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Control charts are vital tools in quality control processes, particularly for monitoring the consistency and stability of manufacturing operations. When dealing with continuous data, such as the volume of cola filled into bottles, individuals or sample means charts are used to determine whether the process remains within acceptable limits. The problem at hand involves calculating the control limits for a process with known mean and standard deviation, drawing on the properties of the normal distribution.
In this scenario, the process mean (μ) is 0.99 liters, the process standard deviation (σ) is 0.05 liters, and the sample size (n) for monitoring is 26 observations. The key objective is to determine the upper control limit (UCL) and lower control limit (LCL) for the sample means that encompass approximately 97% of the sample means if the process is in control. This confidence level corresponds to a probability of 0.97, with 3% total outside the limits, split equally between the two tails of the distribution—1.5% (0.015) in each tail.
The process involves the sampling distribution of the mean. To establish control limits, we first calculate the standard error of the mean (SE), given by:
SE = σ / √n
where:
- σ = 0.05 liters (standard deviation of individual observations)
- n = 26 (sample size)
The calculation yields:
SE = 0.05 / √26 ≈ 0.05 / 5.099 = 0.00981
Next, to find the control limits that encompass 97% of the sample means in a normal distribution, we need to determine the z-value corresponding to the central 97% of the distribution. Since the total area outside the limits is 3%, each tail accounts for 1.5%. The z-value for 98.5% (because 100% - 1.5% in the lower tail) is approximately 2.17, based on standard normal distribution tables, often referred to as Table-A in statistical texts.
The upper and lower control limits for the sample mean are then calculated as:
UCL = μ + z * SE
LCL = μ - z * SE
Substituting the values:
UCL = 0.99 + 2.17 * 0.00981 ≈ 0.99 + 0.0213 = 1.0113
LCL = 0.99 - 2.17 * 0.00981 ≈ 0.99 - 0.0213 = 0.9687
Thus, the control limits that will include roughly 97% of the sample means when the process is in control are approximately:
- Upper Control Limit (UCL): 1.0113 liters
- Lower Control Limit (LCL): 0.9687 liters
These limits are crucial in quality control as they help identify signs of process deviation. If a sample mean falls outside these control limits, it indicates that the process may be out of control, prompting further investigation. Conversely, if the sample means remain within these bounds, the process is considered stable and consistent.
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