Calculate The Sum Of 13 And ½a 25b 56c 13d 12

Calculate The Sum Of 13 And ½a 25b 56c 13d 12 Calculate Th

The assignment involves various arithmetic and algebraic problems, including addition, multiplication, expression interpretation, variable evaluation, unit conversions, interpretation of expressions, and properties of functions and logarithms. The core tasks include calculating sums and products of fractions, translating word problems into algebraic expressions, evaluating expressions for given variable values, converting units, simplifying algebraic expressions, analyzing functions, and simplifying logarithmic expressions. This comprehensive set of problems aims to assess skills in basic mathematics, algebra, functions, and logarithms.

Paper For Above instruction

Mathematics is foundational to scientific reasoning and everyday problem-solving. The current set of problems explores a wide array of topics, ranging from basic arithmetic operations to advanced algebraic and logarithmic concepts. Through deliberate practice of these problems, students develop critical skills such as analytical thinking, precise calculation, and conceptual understanding of mathematical relationships.

Arithmetic Operations and Fractions

The initial questions involve straightforward addition and multiplication of fractions. For example, calculating the sum of 1/3 and 1/2 involves obtaining a common denominator. The least common denominator between 3 and 2 is 6, yielding (2/6) + (3/6) = 5/6. This corresponds to option B. Similarly, multiplying 1/5 by 1/6 involves multiplying numerators and denominators: (1×1)/(5×6) = 1/30, corresponding to choice A.

Interpreting Algebraic Expressions

The problem asks to interpret language into algebraic expressions. "5 more than a number" translates to n + 5, aligning with choice C. "7 times a number" is expressed as 7n, which matches choice B. These translations are fundamental in algebra, enabling the formulation and solving of equations based on word problems.

Evaluating Expressions

Next, the problems involve substituting specific values into algebraic expressions. For instance, evaluating 5(x + 4) - 7 when x = 7 involves substituting x: 5(7 + 4) - 7 = 5(11) - 7 = 55 - 7 = 48. However, since the options provided do not include 48, this suggests reconsideration; the correct substitution yields an answer of 55 if the options were different. Similarly, when x = -4 in the expression x(7 - x) + 5, substituting yields (-4)(7 - (-4)) + 5 = (-4)(11) + 5 = -44 + 5 = -39, which corresponds to option D.

Unit Conversions and Word Problems

Converting measurements is essential in real-world problems. Knowing that there are 16 ounces in a pound, multiplying 16 by 8 yields 128 ounces in 8 pounds (option B). The swimming problem calculates total miles swum: 1/2 mile on day one, 1/4 mile on day two, and 1/8 mile on day three, totaling 7/8 miles, not matching the options. Proper addition of fractions involves converting to common denominators and summing them precisely.

Simplifying Algebraic Expressions

Expressions such as 6(x - 8) - 4(x - 1) + 3x require distribution and combination of like terms. Distributing yields 6x - 48 - 4x + 4 + 3x = (6x - 4x + 3x) + (-48 + 4) = 5x - 44. Simplification agreements with options D or similar, based on accurate calculations.

Temperature Difference

Calculating the difference between temperatures in Phoenix (72°F) and Barrow (-25°F) involves subtracting: 72 - (-25) = 72 + 25 = 97°F, matching option D. This demonstrates the significance of understanding temperature scales and subtraction involving negative numbers.

Properties of Numbers and Variables

Questions involving positive and negative variables, such as a > 0 and b

Pie Slice Fractions

The pie is sliced into 8 pieces, with 2 remaining. Each person desires an equal share of these remaining slices: 2/8 = 1/4 of the original pie, which is option B.

Converting Logarithmic Statements

Converting log9 = -2 to exponential form involves recognizing that log base 9 of some number x equals -2, which translates to 9^(-2) = x, simplifying to 1/81. This conversion illustrates understanding of inverse logarithmic and exponential relationships.

Function and Relation Analysis

Determining if a relation is a function involves verifying that each input x corresponds to exactly one output y. For the set {(-5, -4), (-2, 9), (-1, -2), (-1, 7)}, since x = -1 corresponds to two different y-values, this relation is not a function. Conversely, the equation x + y = 9 expresses y explicitly as y = 9 - x, which is a function.

The quadratic function f(x) = -x^2 - 2x - 6 opens downward (since coefficient of x^2 is negative). Its maximum value occurs at the vertex: x = -b/2a = -(-2)/2(-1) = -1. Substituting x = -1: f(-1) = -1 - 2(-1) - 6 = -1 + 2 - 6 = -5. Because the parabola opens downward, the vertex represents a maximum point, not a minimum.

Logarithmic Simplifications

Simplifying log2 25 involves expressing 25 as 5^2 and applying change of base formulas if needed. Similarly, log6 1/36 simplifies considering that 1/36 = 6^-2, so log6 1/36 = -2. The expression 9 log9(7) simplifies because log9(7) is the exponent to which 9 is raised to produce 7; multiplying by 9 gives 9^1 * log9(7) = 7.

Overall, these problems encapsulate essential concepts in mathematics, including operations, algebra, functions, and logarithms, providing a comprehensive review and application of foundational skills necessary for higher mathematical understanding.

References

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