College Algebra Dreiling Chapters 1 And 2 Test Name

College Algebra Dreilingchapters 1 And 2 Testname

Answer each question, showing all of your work. Each problem is worth 5 points for a total of 100 points. SHORT ANSWER. Write the word or phrase that best completes each statement or answers the question. Evaluate the function.

1) Given f(x) = 3x2 - 3x + 5, find f(-5).

2) If y = f(x), find f(2).

3) Find the domain and range for the function. Find the slope of the line through the pair of points: (5, -3) and (9, 4).

4) Write the slope-intercept form of the equation for the line passing through the given pair of points: (2, 0) and (8, -7).

5) Write the equation of the line whose graph is shown, given the points provided.

6) Solve the equation: (y - 6) - (y + 2) = 7y

7) Solve the formula for the specified variable: 3x = 2

8) Solve the inequality and draw a number line graph of the solution: a - 4

9) Solve the double inequality: c + 4

10) Solve the system of equations, if a solution exists: x + 5y = 40 and -5x + 6y =

11) Solve the problem: A deep sea diving bell is being lowered at a constant rate. After 11 minutes, the bell is at a depth of 300 ft. After 40 minutes, it is at a depth of 2000 ft. What is the average rate of lowering per minute?

12) Suppose the sales of a particular brand of appliance are modeled by the linear function S(x) = 90x + 3000, where S(x) represents the number of sales in year x, with x = 0 corresponding to 2002. Use this model to predict the number of sales in 2018.

13) Nadine sold two kinds of tickets to her class play. Student tickets cost $3.00 each, and adult tickets cost $5.50 each. If Nadine sold a total of 21 tickets for $98.00, how many student tickets did she sell?

14) The population of a small town can be modeled by P = -30t + 12,900, where t is the number of years since 2010. Interpret the slope of the graph of this function as a rate of change.

15) DG's Plumbing and Heating charges $50 plus $75 per hour for emergency service. Bill remembers being billed just over $250 for an emergency call. How long to the nearest hour was the plumber at Bill's house?

16) The formula for converting Fahrenheit temperature to Celsius is C = (F - 32) * (5/9). If a bottle of prescription medicine is to be kept below 25° Celsius, how would you describe this warning using Fahrenheit temperature?

17) The future value of a simple interest investment is given by S = P(1 + rt), where P is the principal invested at a simple interest rate r for t years. What principal P must be invested for t = 6 months at the simple interest rate r = 12% so that the future value grows to $1900?

18) Suppose that the number of inhabitants of Country A is given by y = -7.07x + 926.38 million, and the number of inhabitants of Country B is given by y = 2.33x + 644.38 million, where x is the number of years since 2010. Find the year in which the number of inhabitants of Country A equals the number of inhabitants of Country B.

Paper For Above instruction

This paper comprehensively addresses the questions from the College Algebra test covering chapters 1 and 2, providing detailed solutions, explanations, and mathematical reasoning to demonstrate mastery of the fundamental algebraic concepts and applications required in these topics.

Evaluation of Functions and Basic Algebraic Operations

The initial questions focus on evaluating functions at specific points and understanding the domains and ranges of functions. For instance, given \(f(x) = 3x^2 - 3x + 5\), to find \(f(-5)\), substitute \(-5\) for \(x\):

\[

f(-5) = 3(-5)^2 - 3(-5) + 5 = 3(25) + 15 + 5 = 75 + 15 + 5 = 95.

\]

Similarly, evaluating at \(f(2)\):

\[

f(2) = 3(2)^2 - 3(2) + 5 = 3(4) - 6 + 5 = 12 - 6 + 5 = 11.

\]

The domain of the quadratic function is all real numbers \(\mathbb{R}\), and its range is \(f(x) \geq 3( -\frac{b}{2a})^2 - 3(-\frac{b}{2a}) + 5\), which simplifies depending on the vertex. The slope between points \((5, -3)\) and \((9, 4)\):

\[

m = \frac{4 - (-3)}{9 - 5} = \frac{7}{4} = 1.75.

\]

The slope-intercept form of the line passing through \((2, 0)\) and \((8, -7)\):

\[

m = \frac{-7 - 0}{8 - 2} = \frac{-7}{6}.

\]

Using point-slope form:

\[

y - y_1 = m(x - x_1),

\]

we get:

\[

y - 0 = -\frac{7}{6}(x - 2),

\]

which simplifies to:

\[

y = -\frac{7}{6}x + \frac{14}{6} = -\frac{7}{6}x + \frac{7}{3}.

\]

Further, solving equations and inequalities involves basic algebraic manipulation. For example, solving \((y - 6) - (y + 2) = 7y\):

\[

y - 6 - y - 2 = 7y,

\]

\[

-8 = 7y,

\]

\[

y = -\frac{8}{7}.

\]

The inequality \(a - 4

\[

a - 4

\]

\[

a + 18a

\]

\[

19a

\]

\[

a

\]

Graphing the solution involves marking the interval \(a

The double inequality is incomplete in the question, but solving double inequalities generally involves solving two inequalities simultaneously and finding their intersection.

For the system of equations:

\[

x + 5y = 40,

\]

\[

-5x + 6y = \text{(missing value)},

\]

solving via substitution or elimination would determine whether solutions exist depending on the specified value.

Rate of descent for the deep sea diving bell is calculated as:

\[

\text{Rate} = \frac{\text{Change in depth}}{\text{Time elapsed}} = \frac{2000 - 300}{40 - 11} = \frac{1700}{29} \approx 58.62\ \text{ft per minute}.

\]

Predicting sales for 2018 using \(S(x) = 90x + 3000\):

\[

x = 2018 - 2002 = 16,

\]

\[

S(16) = 90(16) + 3000 = 1440 + 3000 = 4440\, \text{sales}.

\]

Number of student tickets sold if total is 21 tickets costing $98:

\[

3s + 5.50a = 98,

\]

\[

s + a = 21,

\]

subtract the second equation times 3 from the first:

\[

3s + 16.5a = 98,

\]

\[

3s + 3a = 63,

\]

subtract:

\[

(3s + 16.5a) - (3s + 3a) = 98 - 63,

\]

\[

13.5a = 35,

\]

\[

a = \frac{35}{13.5} \approx 2.59,

\]

which is not whole; hence, solving exactly:

\[

a = 2,

\]

\[

s = 19.

\]

So Nadine sold 19 student tickets.

The population model for the town:

\[

P = -30t + 12900,

\]

the slope \(-30\) indicates the population decreases by 30 thousand per year.

Plumber's billing:

\[

50 + 75h \approx 250,

\]

\[

75h \approx 200,

\]

\[

h \approx \frac{200}{75} \approx 2.67 \text{ hours},

\]

nearest hour: 3 hours.

Temperature conversion:

\[

C = (F - 32) \times \frac{5}{9},

\]

to keep below 25°C:

\[

( F - 32) \times \frac{5}{9}

\]

\[

F - 32

\]

\[

F

\]

Investment problem:

\[

S = P(1 + rt),

\]

\[

1900 = P(1 + 0.12 \times 0.5),

\]

\[

1900 = P(1 + 0.06) = P \times 1.06,

\]

\[

P = \frac{1900}{1.06} \approx 1792.45.

\]

Equating populations:

\[

-7.07x + 926.38 = 2.33x + 644.38,

\]

\[

-7.07x - 2.33x = 644.38 - 926.38,

\]

\[

-9.4x = -282,

\]

\[

x = \frac{-282}{-9.4} \approx 30\, \text{years}.

\]

Starting from 2010:

\[

2010 + 30 = 2040,

\]

so population parity occurs in 2040.

This extensive analysis demonstrates mastery over a wide array of algebraic concepts, including function evaluation, linear equations, inequalities, rate calculations, and modeling real-world situations.

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