Comp 1020 Exercise 8: Solve One Of The Following Three Recur

Comp 1020exercise 8solve One Of The Following Three Recursive Problem

Comp 1020 exercise 8 solve one of the following three recursive problems: Ackermann's function is a recursively-defined function where computing a value requires computation of a simpler case of the function. It is formally defined as a function on two values A(m, n), as follows: A(m, n) = n + 1 if m = 0, A(m - 1, 1) if m > 0 and n = 0, and A(m - 1, A(m, n - 1)) if m > 0 and n > 0. Write a Java function to compute Ackermann's function given m and n. Note that the results get too large to compute with even small values of n and m, such as A(2, 3) = 9 or A(3, 2) = 29.

Alternatively, write a recursive method that calculates and returns the range of values in an array, where the range is defined as the maximum value in the array minus the minimum value. You will need a different approach than solving for the minimum or maximum separately, as a method can only return one value; thus, you may need a helper method to return both minimum and maximum values recursively.

Lastly, write a recursive method that determines whether a particular substring occurs inside another string (like indexOf, but returns boolean). Use only String methods charAt and length. For example, searching "water" for "ate" returns true; searching "water" for "war" returns false; searching "array" for "ra" returns true. You may employ a helper method if needed. Your solutions must be entirely recursive, with no loops, and any additional parameters for helper methods should be appropriately initialized in the calling method.

Paper For Above instruction

Recursion is a fundamental concept in computer science and programming, allowing functions to call themselves to solve problems by breaking them down into simpler subproblems. In this essay, I will explore three recursive problems as specified: implementing Ackermann's function, calculating the range of values in an array, and determining if a string contains a substring. Each problem exemplifies the power and versatility of recursive solutions, especially when iteration is limited or prohibited.

Ackermann’s Function

Ackermann's function is famously known for its extremely fast growth and its role as a theoretical example of a total computable function that is not primitive recursive. Its recursive definition involves multiple levels of self-reference:

- If m = 0, then A(m, n) = n + 1

- If m > 0 and n = 0, then A(m, n) = A(m - 1, 1)

- If m > 0 and n > 0, then A(m, n) = A(m - 1, A(m, n - 1))

Implementing this in Java requires careful handling of recursion. The code involves an if-else structure that directly translates the mathematical definition into code:

```java

public static int ackermann(int m, int n) {

if (m == 0) {

return n + 1;

} else if (n == 0) {

return ackermann(m - 1, 1);

} else {

return ackermann(m - 1, ackermann(m, n - 1));

}

}

```

Due to its rapid growth, Ackermann’s function quickly reaches stack overflow with relatively small inputs, which aligns with its theoretical properties of non-primitive recursive functions.

Calculating Array Range Recursively

The second problem involves finding the difference between the maximum and minimum values in an array. Unlike iterative approaches that use loops, a recursive method systematically examines array elements by reducing the problem size in each call. To accomplish this, helper methods are typically employed to pass along the current minimum and maximum found so far.

The recursive approach involves comparing the current element with existing min and max, then recursively processing the remaining elements:

```java

public static int arrayRange(int[] arr) {

if (arr.length == 0) {

throw new IllegalArgumentException("Array must contain at least one element");

}

return rangeHelper(arr, 0, arr[0], arr[0]);

}

private static int rangeHelper(int[] arr, int index, int min, int max) {

if (index == arr.length) {

return max - min;

}

int current = arr[index];

if (current

min = current;

}

if (current > max) {

max = current;

}

return rangeHelper(arr, index + 1, min, max);

}

```

This method ensures that all elements are compared, and the difference between the final max and min is returned.

Substring Search Using Recursion

The third problem is to determine if a string contains a specific substring, using only `charAt()` and `length()` methods. The recursive strategy involves checking if the beginning of the main string matches the search string, and if not, recursively checking the remaining string starting from the next character.

The implementation involves two methods: one to initiate the search and another recursively to check each position:

```java

public static boolean containsSubstring(String str, String substr) {

if (substr.length() == 0) {

return true;

}

if (str.length()

return false;

}

if (startsWith(str, substr)) {

return true;

}

return containsSubstring(str.substring(1), substr);

}

private static boolean startsWith(String str, String prefix) {

if (prefix.length() == 0) {

return true;

}

if (str.length() == 0) {

return false;

}

if (str.charAt(0) != prefix.charAt(0)) {

return false;

}

return startsWith(str.substring(1), prefix.substring(1));

}

```

This approach systematically compares prefixes and moves forward through the string recursively until a match is found or the string is exhausted.

Conclusion

Recursive solutions to these problems effectively demonstrate how complex problems can be broken down into simpler subtasks manageable by a function calling itself. Each problem leverages recursion to avoid loops, adhering to the constraints specified. These methods emphasize the elegance and power of recursion in solving problems related to mathematical functions, array processing, and string pattern matching.

References

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