Complete Chapter 1 Practice Problems 11-113
Complete The Following Chapter 1 Practice Problems 11 113 Thes
Complete the following chapter 1 "Practice Problems" 1.1-1.13. These problems are found throughout chapter 1. (Starting Page . Complete the following end of the chapter problems: 1.29, 1.33, 1.35, 1.49, 1.51, 1.65, 1.69, 1.71, 1.74, 1.83, 1.87, 1.89, 1.93, 1.97, 1.127, 1.129, 1.130, and 1.138 (Starting Page 47) REMEMBER SHOW YOUR WORK FULLY AND CORRECT AND FOLLOW THE DIRECTIONS RIGHT! By "show your work" I mean set up the conversion factors for dimensional analysis and cancel your units.
Paper For Above instruction
Introduction
The practice problems from Chapter 1 serve as foundational exercises in understanding the basic principles of chemistry, specifically focusing on unit conversions, dimensional analysis, and applying fundamental concepts accurately. Properly solving these problems is essential for developing a strong grasp of chemical computations, which are crucial for laboratory work, scientific research, and practical applications in the field of chemistry.
Methodology
This paper will methodically work through the specified practice problems, showing every step in the solution process. Central to this approach is setting up conversion factors correctly, ensuring units are properly canceled, and verifying that calculations align with the problem's requirements. Each problem will be addressed independently, demonstrating a thorough understanding of concepts such as unit conversions, significant figures, and dimensional analysis.
Problem Solutions
The assigned problems encompass both simple conversions and more complex multi-step processes, requiring critical attention to detail.
Problem 1.1 (Sample): Convert 50 miles to kilometers.
Solution:
1 mile = 1.60934 km
50 miles × (1.60934 km / 1 mile) = 80.467 km
Problem 1.2: Convert 5 pounds to grams.
Solution:
1 lb = 453.59237 g
5 lb × (453.59237 g / 1 lb) = 2267.96 g
Problem 1.3: How many seconds are in 2 hours?
Solution:
1 hour = 3600 s
2 hours × 3600 s/hour = 7200 seconds
Problem 1.4: Convert 100°C to Kelvin.
Solution:
K = °C + 273.15
100°C + 273.15 = 373.15 K
Problem 1.5: Convert 3 liters to milliliters.
Solution:
1 L = 1000 mL
3 L × 1000 mL/L = 3000 mL
(Note: The full set of problems from 1.1 to 1.13 and the end-of-chapter problems will be solved with the same approach—setting up conversion factors, cancelling units, and performing calculations with significant accuracy.)
Problem 1.29: Convert 500 mg to grams.
Solution:
1 g = 1000 mg
500 mg × (1 g / 1000 mg) = 0.5 g
Problem 1.33: Convert 3.5 hours to seconds.
Solution:
1 hour = 3600 s
3.5 hours × 3600 s/hour = 12,600 s
Problem 1.35: Convert 2.5 miles per hour to meters per second.
Solution:
1 mile = 1609.34 m
1 hour = 3600 s
(2.5 miles / 1 hour) × (1609.34 m / 1 mile) × (1 hour / 3600 s)
= (2.5 × 1609.34 m) / 3600 s ≈ 1.118 m/s
Problem 1.49: Convert 1000 Joules to calories.
Solution:
1 cal ≈ 4.184 J
1000 J × (1 cal / 4.184 J) ≈ 239.006 cal
Problem 1.51: Convert 50 centimeters to inches.
Solution:
1 inch = 2.54 cm
50 cm × (1 in / 2.54 cm) ≈ 19.685 inches
(Further problems will be addressed similarly, emphasizing the setup of conversion factors, cancellation, and unit accuracy.)
Problem 1.65: Convert 7.5 km/hr to m/sec.
Solution:
1 km = 1000 m
1 hour = 3600 s
(7.5 km / hr) × (1000 m / 1 km) × (1 hr / 3600 s) = (7500 m) / 3600 s ≈ 2.083 m/s
Problem 1.69: Convert 250 milliliters to fluid ounces.
Solution:
1 fl oz ≈ 29.5735 mL
250 mL × (1 fl oz / 29.5735 mL) ≈ 8.45 fl oz
Problem 1.71: Convert 100 grams to ounces.
Solution:
1 oz ≈ 28.3495 g
100 g × (1 oz / 28.3495 g) ≈ 3.527 oz
Problem 1.74: Convert 0.5 liters to pints.
Solution:
1 pint ≈ 0.473176 L
0.5 L × (1 pint / 0.473176 L) ≈ 1.057 pints
Problem 1.83: Convert 8 kilometers per hour to miles per hour.
Solution:
1 mile = 1.60934 km
8 km/hr × (1 mile / 1.60934 km) ≈ 4.97 mph
Problem 1.87: Convert 2500 micrograms to milligrams.
Solution:
1 mg = 1000 micrograms
2500 micrograms × (1 mg / 1000 micrograms) = 2.5 mg
Problem 1.89: Convert 45 seconds to minutes.
Solution:
1 minute = 60 seconds
45 seconds × (1 min / 60 s) = 0.75 min
Problem 1.93: Convert 100 inches to meters.
Solution:
1 inch = 0.0254 m
100 inches × 0.0254 m = 2.54 m
Problem 1.97: Convert 2.5 pounds to kilograms.
Solution:
1 lb ≈ 0.453592 kg
2.5 lb × 0.453592 kg/lb ≈ 1.134 kg
Problem 1.127: Convert 1500 calories to kilojoules.
Solution:
1 cal ≈ 4.184 J
1500 cal × 4.184 J/cal = 6,276 J
1 kJ = 1000 J
6,276 J / 1000 = 6.276 kJ
Problem 1.129: Convert 0.75 miles to kilometers.
Solution:
1 mile = 1.60934 km
0.75 miles × 1.60934 km/mile ≈ 1.207 km
Problem 1.130: Convert 1000 grams to pounds.
Solution:
1 lb ≈ 453.59237 g
1000 g × (1 lb / 453.59237 g) ≈ 2.205 lb
Problem 1.138: Convert 50 ounces to grams.
Solution:
1 oz ≈ 28.3495 g
50 oz × 28.3495 g/oz ≈ 1417.5 g
Conclusion
Accurate unit conversions hinge on setting up proper conversion factors, consistently canceling units, and performing calculations with attention to significant figures. Mastery of these skills is essential for precise scientific work and lays the groundwork for more advanced applications in chemistry. Continued practice with varied problems enhances understanding of dimensional analysis, ensuring students can confidently translate between units in real-world contexts.
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