Create An Exponential Function Which Models The Bunny Popula
Create an exponential function which models the bunny population as a function of years after 2009
The population of bunnies in 2009 is 500, and in 2013 it increases to 850. To model this exponential growth, use the form:
\( P(t) = P_0 \times r^t \), where \( P_0 \) is the initial population at year 2009 and \( t \) is the number of years after 2009.
Given \( P(0) = 500 \) and \( P(4) = 850 \), we have:
\( 850 = 500 \times r^4 \)
Dividing both sides by 500:
\( r^4 = \frac{850}{500} = 1.7 \)
Taking the fourth root of both sides:
\( r = \sqrt[4]{1.7} \approx 1.1454 \)
Therefore, the modeled function is:
\( P(t) = 500 \times (1.1454)^t \), where \( t \) is the years after 2009.
Assuming that the value of bunnies is exponential, how much is the bunny worth in 2017?
The bunny's value is $3000 in 2005 (which corresponds to \( t = -4 \) if 2009 is \( t=0 \)), and $600 in 2013 (\( t = 4 \)).
Set the exponential valuation model:
\( V(t) = V_0 \times r^t \), where \( V_0 \) is the value at year 2005.
Using the data points:
\( 600 = 3000 \times r^4 \Rightarrow r^4 = \frac{600}{3000} = 0.2 \)
Taking the 4th root:
\( r = \sqrt[4]{0.2} \approx 0.6687 \)
Find the value in 2017 (\( t=8 \), since 2017 is 8 years after 2009):
\( V(8) = V_0 \times r^8 \)
First, find \( V_0 \) (value in 2005):
\( V_0 = 3000 \times r^{−4} \) (since 2005 is 4 years before 2009)
\( V_0 = 3000 \times (0.6687)^{−4} \) ≈ 3000 × (1/0.6687)^4 ≈ 3000 × (1.4957)^4 ≈ 3000 × 5.0 ≈ 15,000
Now, compute the value in 2017 (t=8):
\( V(8) = 15,000 \times (0.6687)^8 \)
\( V(8) ≈ 15,000 \times (0.6687)^8 ≈ 15,000 \times 0.199 \approx 2985 \)
Thus, the bunny is worth approximately $2,985 in 2017.
Create a function which models the following graph
Unfortunately, without the actual graph, assumptions can be made for typical exponential types. For example, if the graph is an exponential decay or growth, the general form is:
\( f(x) = a \times b^x + c \), where \( a \) is the amplitude, \( b \) is the base, and \( c \) is the vertical shift.
Assuming an exponential decay with the graph crossing specific points, we can derive parameters based on those points. For instance, suppose the function passes through (0,1) and (2,0.25).
From \( f(0) = 1 \), we get:
\( 1 = a \times b^0 + c = a + c \).
And from \( f(2) = 0.25 \):
\( 0.25 = a \times b^2 + c \).
Assuming \( c = 0 \) (no vertical shift), then:
\( a = 1 \), and \( 0.25 = 1 \times b^2 \Rightarrow b^2 = 0.25 \Rightarrow b = 0.5 \).
Thus, a possible model is:
\( f(x) = 1 \times 0.5^x \).
Given the basic function f(x) = log3(x), find a function which (a) shifts f(x) upwards 5 units AND (b) shifts f(x) to the right by 8 units
The original function: \( f(x) = \log_3(x) \).
(a) To shift upwards by 5 units:
\( f_1(x) = \log_3(x) + 5 \).
(b) To shift to the right by 8 units:
\( f_2(x) = \log_3(x - 8) \).
Combining both transformations, the resulting function is:
\( f(x) = \log_3(x - 8) + 5 \).
Paper For Above instruction
The assignment involves creating models and understanding functions related to exponential growth, decay, and transformations. It begins with modeling bunny population growth using an exponential function, requiring calculation of the growth rate parameter based on initial and later populations. Similarly, it involves modeling the valuation of a prized bunny over time, based on exponential decline or growth, and estimating its worth in a future year. Additionally, the task includes constructing an exponential function to fit a given graph conceptually, using assumed points. Lastly, the instructions require transforming a logarithmic function through shifts both upward and horizontally, highlighting understanding of function transformations. This exercise bridges theoretical understanding of exponential and logarithmic functions with practical modeling and real-world applications, such as population dynamics and valuation analysis.
Throughout, proper application of algebraic techniques, roots, exponents, and translations are necessary. The focus is on demonstrating comprehension of the models and their parameters, ensuring clarity in reasoning, and performing accurate calculations. The ability to interpret and manipulate these functions is crucial in various academic and real-world contexts, especially in fields like biology, economics, and social sciences. Such exercises reinforce the importance of mathematical literacy in analyzing patterns, making predictions, and understanding the impact of different variables on real-world phenomena.
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