Formulate And Solve A Linear Programming Model For This Case

Formulate and solve a Linear Programming Model for this case

Formulate and solve a Linear Programming Model for this case

The case involves Julia Robertson considering leasing a food booth at Tech stadium during home football games. Her goal is to maximize profits by selling pizza slices, hot dogs, and barbecue sandwiches while managing various constraints such as budget, oven space, and sales demand. To approach this, we need to formulate a linear programming (LP) model that captures the essential decision variables, objective function, and constraints, and then solve it to determine optimal quantities of each item.

Decision Variables:

Let:

- \( x_1 \) = number of pizza slices sold per game

- \( x_2 \) = number of hot dogs sold per game

- \( x_3 \) = number of barbecue sandwiches sold per game

Objective Function:

Maximum profit equates to total revenue minus total costs. The selling prices and ingredient costs are given:

- Pizza: Selling price = \$1.50 per slice; Cost per 8 slices = \$6; so, cost per slice = \$0.75; profit per slice = \$1.50 - \$0.75 = \$0.75

- Hot dog: Selling price = \$1.50; cost = \$0.45; profit = \$1.05

- Barbecue sandwich: Selling price = \$2.25; cost = \$0.90; profit = \$1.35

Thus, the objective function to maximize profit:

\[

Z = 0.75x_1 + 1.05x_2 + 1.35x_3

\]

Constraints:

Budget constraint:

Initial cash available is \$1,500; costs per item:

- Pizza: \( 6 \) dollars per pizza, includes 8 slices, so \( 6x_{p} \), but since we consider slices directly, total cost for slices is \( 0.75x_1 \). For initial purchase, assume the total cost is based on per-unit costs:

\( 0.75x_1 + 0.45x_2 + 0.90x_3 \leq 1500 \)

Oven space constraint:

Oven has 16 shelves measuring 3 ft x 4 ft = 12 sq ft per shelf, total 48 sq ft (or 27648 sq inches).

The oven is used twice per game, so the total space used must not exceed total oven capacity:

- Space per slice of pizza: approximately 24 sq in

- Space needed for \( x_1 \) slices: \( 24x_1 \)

- Space per hot dog: \( 16 \) sq in

- Space needed for \( x_2 \) hot dogs: \( 16x_2 \)

- Space per BBQ sandwich: approximately 25 sq in

- Space needed for \( x_3 \) sandwiches: \( 25x_3 \)

Total space used for one set:

\[

24x_1 + 16x_2 + 25x_3

\]

Total for two uses per game:

\[

2 \times (24x_1 + 16x_2 + 25x_3) \leq 55296

\]

Demand constraints:

- Pizza slices at least as many as hot dogs and BBQ sandwiches combined:

\[

x_1 \geq x_2 + x_3

\]

- Hot dogs at least twice the barbecue sandwiches:

\[

x_2 \geq 2x_3

\]

- Non-negativity:

\[

x_1, x_2, x_3 \geq 0

\]

Solving the model:

This LP can be implemented and solved using Excel Solver or QM for Windows by setting the decision variables, defining the objective function and constraints accordingly. The optimal solution will provide the quantities \( x_1, x_2, x_3 \) that maximize profit. The computed profit, after solution, indicates the viability of the business model.

Additional financial considerations:

- Shadow price for budget: By analyzing the sensitivity report, Julia can determine how much additional profit she can generate per extra dollar borrowed, considering the shadow price (dual value). If, for instance, the shadow price is \$2 per dollar, borrowing up to the limit of the sensitivity range can increase her profit substantially, but only within the valid bounds.

- Paying a friend: The ability to pay a friend \$100 per game depends on the net profit after expenses. If the profit per game exceeds \$100, she can proceed; otherwise, not.

- Uncertainties impact: Unforeseen factors such as lower-than-expected sales, ingredient price fluctuations, or unforeseen costs can significantly affect profitability. Analyzing these uncertainties involves conducting a risk analysis, considering profit margin variability, and assessing whether the projected \$1,000 profit per game justifies ongoing operation.

Overall, the LP model provides a strategic framework to optimize sales, while financial sensitivity analysis and risk assessment inform decisions about borrowing, staffing, and whether to proceed given potential uncertainties.

Paper For Above instruction

Julia Robertson's decision to lease and operate a food booth at Tech stadium encapsulates a classic optimization problem that leverages linear programming to maximize profit within specified constraints. The process involves formalizing her decisions through variables, objective function, and constraints, then solving the model to identify optimal quantities of pizza slices, hot dogs, and barbecue sandwiches to sell per game. This structured approach ensures Julia can efficiently utilize her resources — both financial and spatial — and streamline her operations to achieve her profit goals.

Formulating the Linear Programming Model:

The decision variables are \( x_1 \), \( x_2 \), and \( x_3 \), representing the quantities of pizza slices, hot dogs, and barbecue sandwiches sold per game, respectively. Julia’s aim is to maximize her profit, which is derived from selling these items at given prices minus their costs. The profit per unit for each item is calculated as the selling price minus the unit cost:

- Pizza: Selling price = \$1.50 per slice; cost = \$0.75 per slice; profit = \$0.75

- Hot dog: Selling price = \$1.50; cost = \$0.45; profit = \$1.05

- Barbecue sandwich: Selling price = \$2.25; cost = \$0.90; profit = \$1.35

Thus, the objective function articulates:

\[

\text{Maximize } Z = 0.75x_1 + 1.05x_2 + 1.35x_3

\]

Constraints:

1. Budget constraint: The initial cash of \$1,500 limits the total investment in ingredients and supplies:

\[

0.75x_1 + 0.45x_2 + 0.90x_3 \leq 1500

\]

2. Oven space constraint: The oven's capacity is used twice per game, with dimensions totaling 27,648 sq in available per cycle. The space required for each product is calculated based on their size:

- Pizza slices require about 24 sq in each

- Hot dogs about 16 sq in each

- Sandwiches about 25 sq in each

Total space needed for all items per cycle:

\[

24x_1 + 16x_2 + 25x_3

\]

Total for two uses per game:

\[

2 \times (24x_1 + 16x_2 + 25x_3) \leq 55296

\]

3. Demand constraints:

- The number of pizza slices should be at least as many as hot dogs and sandwiches combined:

\[

x_1 \geq x_2 + x_3

\]

- The number of hot dogs should be at least twice the number of sandwiches:

\[

x_2 \geq 2x_3

\]

4. Non-negativity:

\[

x_1, x_2, x_3 \geq 0

\]

Solving the LP:

Using software like Excel Solver or QM for Windows, Julia can set these variables and constraints to find the optimal solution. The solution will provide the quantities \( x_1, x_2, x_3 \) that maximize her profit, as well as the expected profit, assisting her in making effective operational decisions.

Financial and Risk Analysis:

- Shadow Price of Budget: The dual value for the budget tells Julia how much additional profit she can generate per extra dollar borrowed within the sensitivity range. For example, a shadow price of \$2 indicates an increase of \$2 in profit per dollar borrowed, up to the maximum admissible increase in her budget.

- Paying a Friend: Whether Julia can afford to pay her friend \$100 per game depends on her net profit after expenses. If her profit exceeds this amount, then staffing assistance is feasible.

- Uncertainty Impact: Real-world uncertainties such as sales fluctuations, ingredient price increases, or unforeseen costs could reduce profits. Conducting a risk analysis by varying key parameters helps Julia understand the robustness of her plan. If her projected profit of \$1,000 per game is marginal under uncertain conditions, she should consider contingency plans, such as cost reduction strategies or sales improvements, to ensure profitability.

In conclusion, the linear programming approach provides Julia with a structured framework to optimize her food booth's operations, while sensitivity and risk analyses guide her financial planning and strategic decisions.

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