Homework Assignment 2 (2 Pts Each) ✓ Solved

Name: Class: Date: Homework Assignment 2 (2pts each) Enter

1. What was the average rate of change of sales between 1989 and 1999? __________ CD players/year

2. Determine the average rate of change of the function f(x) = x³ - 5x² between x = 0 and x = 10.

3. Use the given graphs of f and g to evaluate the expression. __________

4. Use and to evaluate the expression. __________

5. Determine the average rate of change of the function f(x) = 9 - 7x between x = 2 and x = 3.

6. Use the given graphs of f and g to evaluate the expression. __________

7. Use the given graphs of f and g to evaluate the expression. __________

8. A man is running around a circular track 200 m in circumference. What was the man's average speed (rate) between 70 s and 164 s? __________ m/s

9. Determine the average rate of change of the function f(x) = x + x⁴ between x = 0 and x = 2.

10. Determine the average rate of change of the function f(t) = t² - 4t between t = -5 and t = -4.

Paper For Above Instructions

The following assignment addresses calculations related to the average rate of change and other evaluations based on functions and real-world scenarios.

1. Average Rate of Change of CD Sales (1989-1999)

The average rate of change of CD players sold from 1989 to 1999 can be calculated using the formula for average rate of change:

Average Rate of Change = (f(b) - f(a)) / (b - a)

Let’s denote:

  • a = 1989
  • b = 1999
  • f(1989) = x
  • f(1999) = y

The average rate of change then is:

(y - x) / (1999 - 1989) = (y - x) / 10

Replace x and y with specific sales data (not provided here) to finalize the average rate of change.

2. Average Rate of Change for f(x) = x³ - 5x² (from 0 to 10)

We find:

f(0) = 0³ - 5(0)² = 0

f(10) = 10³ - 5(10)² = 1000 - 500 = 500

Using the average rate of change formula:

Average Rate of Change = (f(10) - f(0)) / (10 - 0) = (500 - 0) / 10 = 50

3. Evaluation using Graphs of f and g

This step requires the specific graphical details of functions f and g, which are not provided in the assignment. Typically, one would identify values from the graphs at the necessary points.

Solution: Evaluating would lead to a specific outcome depending on the graph locations.

4. Evaluation of an Expression

Similar to the above, this would require knowing values or functions to evaluate the specified expression.

Solution: Substitute known values as per the graphs given for functions f and g.

5. Average Rate of Change for f(x) = 9 - 7x (from 2 to 3)

Calculating:

f(2) = 9 - 7(2) = 9 - 14 = -5

f(3) = 9 - 7(3) = 9 - 21 = -12

So,

Average Rate of Change = (-12 - (-5)) / (3 - 2) = (-12 + 5) / 1 = -7

6-7. Evaluating Expressions using Graphs of f and g

As with sections 3 and 4, the evaluations depend on the positions represented on the graphs, needing analysis.

8. Average Speed Around a Circular Track

Distance = 200 m; for average speed between 70 s and 164 s, we first need the distance covered in that time.

Let’s denote distance covered as d.

Using the stopwatch observations, we calculate total time:

Time = 164 s - 70 s = 94 s

Average Speed = Total Distance / Total Time. If d is determined from the data, plug it into:

Average Speed = d / 94 s

9. Average Rate of Change for f(x) = x + x⁴ (from 0 to 2)

Calculating:

f(0) = 0 + 0⁴ = 0

f(2) = 2 + 2⁴ = 2 + 16 = 18

Average Rate of Change = (f(2) - f(0)) / (2 - 0) = (18 - 0) / 2 = 9

10. Average Rate of Change for f(t) = t² - 4t (from -5 to -4)

Calculating:

f(-5) = (-5)² - 4(-5) = 25 + 20 = 45

f(-4) = (-4)² - 4(-4) = 16 + 16 = 32

Average Rate of Change = (32 - 45) / (-4 - (-5)) = (-13) / (1) = -13

References

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