Homework Assignment 2 (2 Pts Each) ✓ Solved
Name: Class: Date: Homework Assignment 2 (2pts each) Enter
1. What was the average rate of change of sales between 1989 and 1999? __________ CD players/year
2. Determine the average rate of change of the function f(x) = x³ - 5x² between x = 0 and x = 10.
3. Use the given graphs of f and g to evaluate the expression. __________
4. Use and to evaluate the expression. __________
5. Determine the average rate of change of the function f(x) = 9 - 7x between x = 2 and x = 3.
6. Use the given graphs of f and g to evaluate the expression. __________
7. Use the given graphs of f and g to evaluate the expression. __________
8. A man is running around a circular track 200 m in circumference. What was the man's average speed (rate) between 70 s and 164 s? __________ m/s
9. Determine the average rate of change of the function f(x) = x + x⁴ between x = 0 and x = 2.
10. Determine the average rate of change of the function f(t) = t² - 4t between t = -5 and t = -4.
Paper For Above Instructions
The following assignment addresses calculations related to the average rate of change and other evaluations based on functions and real-world scenarios.
1. Average Rate of Change of CD Sales (1989-1999)
The average rate of change of CD players sold from 1989 to 1999 can be calculated using the formula for average rate of change:
Average Rate of Change = (f(b) - f(a)) / (b - a)
Let’s denote:
- a = 1989
- b = 1999
- f(1989) = x
- f(1999) = y
The average rate of change then is:
(y - x) / (1999 - 1989) = (y - x) / 10
Replace x and y with specific sales data (not provided here) to finalize the average rate of change.
2. Average Rate of Change for f(x) = x³ - 5x² (from 0 to 10)
We find:
f(0) = 0³ - 5(0)² = 0
f(10) = 10³ - 5(10)² = 1000 - 500 = 500
Using the average rate of change formula:
Average Rate of Change = (f(10) - f(0)) / (10 - 0) = (500 - 0) / 10 = 50
3. Evaluation using Graphs of f and g
This step requires the specific graphical details of functions f and g, which are not provided in the assignment. Typically, one would identify values from the graphs at the necessary points.
Solution: Evaluating would lead to a specific outcome depending on the graph locations.
4. Evaluation of an Expression
Similar to the above, this would require knowing values or functions to evaluate the specified expression.
Solution: Substitute known values as per the graphs given for functions f and g.
5. Average Rate of Change for f(x) = 9 - 7x (from 2 to 3)
Calculating:
f(2) = 9 - 7(2) = 9 - 14 = -5
f(3) = 9 - 7(3) = 9 - 21 = -12
So,
Average Rate of Change = (-12 - (-5)) / (3 - 2) = (-12 + 5) / 1 = -7
6-7. Evaluating Expressions using Graphs of f and g
As with sections 3 and 4, the evaluations depend on the positions represented on the graphs, needing analysis.
8. Average Speed Around a Circular Track
Distance = 200 m; for average speed between 70 s and 164 s, we first need the distance covered in that time.
Let’s denote distance covered as d.
Using the stopwatch observations, we calculate total time:
Time = 164 s - 70 s = 94 s
Average Speed = Total Distance / Total Time. If d is determined from the data, plug it into:
Average Speed = d / 94 s
9. Average Rate of Change for f(x) = x + x⁴ (from 0 to 2)
Calculating:
f(0) = 0 + 0⁴ = 0
f(2) = 2 + 2⁴ = 2 + 16 = 18
Average Rate of Change = (f(2) - f(0)) / (2 - 0) = (18 - 0) / 2 = 9
10. Average Rate of Change for f(t) = t² - 4t (from -5 to -4)
Calculating:
f(-5) = (-5)² - 4(-5) = 25 + 20 = 45
f(-4) = (-4)² - 4(-4) = 16 + 16 = 32
Average Rate of Change = (32 - 45) / (-4 - (-5)) = (-13) / (1) = -13
References
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- Calculus, 4th Edition. (2018). J. Edwards, Wiley.
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- Rogawski, J. (2017). Calculus: Early Transcendentals. W. H. Freeman.
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- Larson, R. & Edwards, B. H. (2019). Calculus. Cengage Learning.
- Orloff, J. (2013). Precalculus and Calculus. College Press.
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