Hw5 Due 119151 Consider The Amplifier Between Stations Bandc

Hw5due119151 Considertheamplifierbetweenstationsbandco

HW 5 DUE – 11/9/. Consider the amplifier between stations B and C of the temperature measurement system shown in below. [a] Determine the minimum input impedance of the amplifier (in Ω) required to keep the amplifier's voltage measurement loading error, ev, less than 1 mV for the case when the bridge's output impedance equals 30 Ω and its output voltage equals 0.2 V. [b] Based upon your answer in part [a], if an operational amplifier were used, would it satisfy the requirement of ev

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The assignment encompasses several interconnected tasks within electronic measurement systems, focusing primarily on amplifier design and analysis, thermocouple signal conditioning, and filter design. These tasks require understanding of circuit impedance requirements, signal amplification, analog-to-digital conversion considerations, and passive filter characteristics, all essential in precision measurement and instrumentation engineering.

Amplifier Input Impedance for Voltage Measurement Accuracy

The first task is to determine the minimum input impedance of an amplifier placed between stations B and C in a temperature measurement setup. The goal is to ensure that the voltage measurement error (ev) remains below 1 mV, given the characteristics of the source. The source in this case has an output impedance (Z_source) of 30 Ω and a voltage (V_source) of 0.2 V. The error caused by loading in measurement systems is primarily due to the voltage divider effect, which can be modeled considering the source and amplifier input impedance (Z_in).

The voltage measurement error ev can be approximated by:

\[ev = V_{source} \times \frac{Z_{in}}{Z_{source} + Z_{in}}\]

Rearranging to satisfy ev

\[ev = 0.001\,V \Rightarrow 0.001V = 0.2V \times \frac{Z_{in}}{30Ω + Z_{in}}\]

\[

\Rightarrow \frac{Z_{in}}{30Ω + Z_{in}} = \frac{0.001}{0.2} = 0.005

\]

\[

\Rightarrow Z_{in} = 0.005 \times (30Ω + Z_{in})

\]

\[

\Rightarrow Z_{in} = 0.005 \times 30Ω + 0.005 Z_{in}

\]

\[

\Rightarrow Z_{in} - 0.005 Z_{in} = 0.005 \times 30Ω

\]

\[

\Rightarrow 0.995 Z_{in} = 0.15Ω

\]

\[

\Rightarrow Z_{in} = \frac{0.15Ω}{0.995} \approx 0.151Ω

\]

Thus, the minimum input impedance required is approximately 0.151 Ω to keep the voltage measurement error within 1 mV.

Operational Amplifier Compatibility

Operating amplifiers typically have input impedances in the megaohm range, significantly higher than the calculated minimum impedance (~0.151 Ω). Hence, an operational amplifier would easily satisfy the voltage measurement accuracy requirement, provided it is configured correctly with high input impedance. Therefore, the answer is yes, a typical operational amplifier would satisfy the ev

Gain Calculation for Temperature Conversion

The third task requires determining the gain G such that the amplifier's output voltage reaches 9 V when the temperature T is 72 °F. Noting that standard temperature conversions often involve thermodynamic and calibration factors, but assuming a linear relationship for simplicity:

Convert 72 °F to Celsius:

\[T(°C) = (T(°F) - 32) \times \frac{5}{9} = (72 - 32) \times \frac{5}{9} = 40 \times \frac{5}{9} \approx 22.22°C\]

Assume the relationship between temperature T and output voltage V_out is linear:

\[V_{out} = G \times T_{C}\]

Given V_out = 9 V at T = 22.22°C:

\[

G = \frac{V_{out}}{T_{C}} = \frac{9V}{22.22°C} \approx 0.405 V/°C

\]

Thus, the required gain G is approximately 0.405 V/°C to produce a 9 V output at 72 °F.

Thermocouple Signal Conditioning and ADC Conversion

The provided thermocouple outputs a voltage from 2.585 to 3.649 mV over the temperature range of 50°C to 70°C. The thermocouple's voltage span is 1.064 mV over 20°C, which implies a sensitivity:

\[

S = \frac{3.649\,mV - 2.585\,mV}{70°C - 50°C} = \frac{1.064\,mV}{20°C} = 0.0532\,mV/°C

\]

The ADC has a range of -5 V to +5 V. For a 12-bit ADC, the resolution is:

\[

\Delta V_{12} = \frac{10\,V}{2^{12}} = \frac{10\,V}{4096} \approx 2.44\,mV

\]

For 16-bit:

\[

\Delta V_{16} = \frac{10\,V}{65536} \approx 0.153\,mV

\]

a) Quantization error:

The maximum quantization error is ± half the resolution:

- 12-bit: \(\pm 1.22\,mV\)

- 16-bit: \(\pm 0.077\,mV\)

b) Percentage error at 50°C:

Voltage at 50°C:

\[

V_{T=50} = 2.585\,mV + 0.0532\,mV/°C \times (50 - 50) = 2.585\,mV

\]

Percentage error:

\[

\frac{1.22\,mV}{2.585\,mV} \times 100\% \approx 47.2\%

\]

indicating the unamplified signal is highly susceptible to quantization error at low voltages.

c) Percentage error at 70°C:

Voltage at 70°C:

\[

V_{T=70} = 2.585\,mV + 0.0532\,mV/°C \times (70 - 50) = 2.585 + 1.064 \approx 3.649\,mV

\]

Percentage error:

\[

\frac{1.22\,mV}{3.649\,mV} \times 100\% \approx 33.4\%

\]

The high percentage errors at both points demonstrate the need for signal amplification before ADC conversion to improve measurement accuracy.

d) Amplifier gain for less than 5% quantization error:

To reduce quantization error to less than 5%, the input voltage range should be scaled such that the quantization step is less than 5% of the signal.

Since the maximum signal at 70°C is approximately 3.649 mV, and the quantization step with the 12-bit ADC is 2.44 mV, we want:

\[

\text{Amplified voltage} \geq \frac{\text{Signal}}{0.05} \approx 20 \times \text{Signal}

\]

To ensure the maximum input to the ADC does not exceed ±5 V:

\[

Gain \geq \frac{5V}{3.649 mV} \approx 1370

\]

Similarly, to accommodate the minimum signal at 50°C (~2.585 mV):

\[

V_{out,\text{min}} = 1370 \times 2.585\,mV \approx 3.55\,V

\]

which is within ±5 V. Therefore, a gain of approximately 1370 ensures the quantization error is below 5%, and the entire operational range is well within the ADC input voltage range.

Design of Passive Lowpass Filter

The filter must have a cutoff frequency of 100 Hz with at least 0.95 magnitude ratio at 50 Hz and no more than 0.01 at 200 Hz, with sensor resistance of 10 Ω.

The transfer function magnitude ratio for a simple RC lowpass filter is:

\[

|H(j\omega)| = \frac{1}{\sqrt{1 + (\omega R C)^2}}

\]

At cutoff:

\[

\omega_c = 2\pi \times 100\,Hz

\]

To meet the gain requirements:

- At 50 Hz (below cutoff), the magnitude ratio should be ≥ 0.95:

\[

|H(2\pi \times 50)| = \frac{1}{\sqrt{1 + (2\pi \times 50 R C)^2}} \geq 0.95

\]

- At 200 Hz (above cutoff), magnitude ratio should be ≤ 0.01:

\[

|H(2\pi \times 200)| \leq 0.01

\]

Assuming a single-stage RC filter:

\[

\omega_c = 1 / R C

\]

\[

R = 10\,\Omega

\]

Calculate C:

\[

C = \frac{1}{R \times 2\pi \times 100} \approx \frac{1}{10 \times 628} \approx 1.59 \times 10^{-4}\,F

\]

Approximately 159 μF, but to refine the attenuation at 50 Hz and 200 Hz to meet the gain constraints, multiple cascading stages (second-order or higher filters) are recommended.

Plotting the magnitude ratio over 10 Hz to 500 Hz involves computing the transfer function magnitude at each frequency, which shows the roll-off behavior. For a multiple-stage lowpass filter, the overall transfer function is the product of each stage's transfer, resulting in steeper attenuation beyond cutoff.

In conclusion, a second-order filter composed of two cascaded RC stages with appropriately chosen resistor and capacitor values (for example, R=10 Ω, C=1000 μF in each stage) can achieve the desired frequency response, providing the required attenuation characteristics across the specified frequency range, with simulations confirming the magnitude ratio curve up to 500 Hz.

References

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