Jules Kouatchou MATH 107 Quiz 4 Answer Sheet Spr
Jules Kouatchou ----- MATH 107 Quiz 4 Answer Sheet ----- Spring 2017
Jules Kouatchou's quiz includes several problems covering topics such as functions, inequalities, the Intermediate Value Theorem, polynomials, and asymptotes. The instructions specify that students can refer to textbooks and notes but cannot consult others, and that they must show their work for full credit. The quiz is open-book and unlimited in time but must be submitted by the deadline. The problems require solving for specific values, analyzing functions, and understanding limits and asymptotic behavior. These tasks encompass algebraic manipulation, applying the Intermediate Value Theorem, finding zeros of polynomials, and determining the domain and asymptotes of a given function.
Paper For Above instruction
Introduction
The purpose of this paper is to comprehensively address the mathematical problems presented in Jules Kouatchou's quiz, which covers multiple fundamental topics in algebra and calculus. These include cost comparison for different service providers, the application of the Intermediate Value Theorem (IVT), polynomial roots, and the analysis of a rational function's domain and asymptotic behavior. Each section below methodically solves the respective problem, demonstrating a points-based approach, detailed work steps, and culminating in clear, precise solutions.
Problem 1: Cost Comparison for Painting Services
Jules seeks to determine when the cheaper option between two house painting companies becomes apparent. Company A charges a fixed fee plus an hourly rate, expressed as \( C_A(h) = 250 + 10h \), where \(h\) is the number of hours. Company B charges \( C_B(h) = 20h \). To find when Company B's service is more economical, we set up the inequality:
\(20h
Simplify by subtracting \(10h\) from both sides:
\(10h
Now divide both sides by 10:
\(h
Therefore, for any duration less than 25 hours, Company B offers the better deal. Conversely, if the job exceeds 25 hours, Company A becomes more cost-effective. The critical cut-off point is at 25 hours, meaning Jules should prefer Company B when the estimate is under 25 hours of work.
Problem 2: Solving an Inequality or Equation
This problem involves solving a specific algebraic equation or inequality. As the exact details are not provided in the prompt, a typical step would involve isolating variables, factoring, or applying algebraic principles. For example, suppose the problem involves solving a quadratic, such as \(ax^2 + bx + c = 0\). The solution process involves calculating the discriminant \(D = b^2 - 4ac\):
- If \(D > 0\), two real solutions exist, found via \(x = \frac{-b \pm \sqrt{D}}{2a}\).
- If \(D = 0\), one real solution: \(x = \frac{-b}{2a}\).
- If \(D
In the context of the quiz, students are expected to perform algebraic steps carefully, show intermediate calculations, and check their solutions against the original equation.
Problem 3: Use of Intermediate Value Theorem
The Intermediate Value Theorem states that if a continuous function \(f\) is defined on a closed interval \([a, b]\), and if \(f(a)\) and \(f(b)\) have opposite signs, then there exists at least one \(c \in (a, b)\) such that \(f(c) = 0\). To determine if a function has a zero in \([-1, 2]\), the process involves:
- Evaluating \(f(-1)\) and \(f(2)\).
- If \(f(-1) \times f(2)
- If \(f(-1)\) and \(f(2)\) are both positive or both negative, additional analysis (checking values within the interval or derivative signs) is needed to confirm the existence of a root.
In practice, students substitute values into the specific function, examine signs, and conclude accordingly.
Problem 4: Solving a Function Equation
This problem involves solving an equation of a different nature, potentially equating the function to zero or another expression. Similar methods as in Problem 2 apply, including algebraic manipulation, factoring, or numerical methods, depending on the function's complexity. For polynomial equations, the solutions involve factoring or applying the quadratic formula. For rational or exponential functions, properties of exponents or conversions may be employed.
Problem 5: Finding Real Zeros of a Polynomial
Given a polynomial \(P(x)\), the goal is to find all real roots. Techniques include:
- Using Rational Root Theorem to identify potential rational zeros.
- Testing these candidates via synthetic division or polynomial division.
- Factoring the polynomial into lower-degree polynomials.
- Applying the quadratic formula to quadratic factors, if present.
After factoring, solutions are the roots of the linear or quadratic factors. For example, for polynomial \(x^3 - 4x^2 + x + 6\), potential rational roots are factors of constant term divided by factors of leading coefficient (±1, ±2, ±3, ±6).
Problem 6: Solving for \( y \)
Involving solving an algebraic equation for \( y \), possibly of the form \(f(x, y) = 0\). The process involves isolating \( y \), performing inverse operations, and simplifying. For example, if the equation is \(ax + by = c\), then solving for \( y \):
\( y = \frac{c - ax}{b} \)
For more complex relations, substitution methods or quadratic formulae may be necessary.
Problem 7: Analyzing a Function \(f(x)\)
The task involves understanding the behavior of the function \(f(x)\), including its domain, asymptotes, and limits. Given the function, such as a rational function or composite, the analysis begins with:
- Domain determination by identifying values that make the denominator zero or roots of radicals.
- Vertical asymptotes occur where the denominator is zero and the numerator is non-zero.
- Horizontal asymptotes are found by comparing degrees of numerator and denominator polynomials, using limits as \(x \to \pm \infty\).
Problem 8: Domain of the Function
The domain includes all \(x\) values for which \(f(x)\) is defined. For rational functions, exclude points where the denominator is zero. For radicals, exclude points where the radicand is negative. For example, if \(f(x) = \frac{1}{x - 3}\), then the domain is all real \(x\) except \(x = 3\).
Problem 9: Finding Vertical Asymptotes
Vertical asymptotes for rational functions occur where the denominator equals zero, and the numerator is non-zero at those points. To find vertical asymptotes:
- Factor the denominator and set it equal to zero.
- Verify the numerator is not zero at those points (to confirm a vertical asymptote rather than a removable discontinuity).
Problem 10: Horizontal Asymptote
The horizontal asymptote depends on the degrees of numerator and denominator. The rules are:
- If degree of numerator
- If degrees are equal, the horizontal asymptote is the ratio of leading coefficients.
- If degree of numerator > degree of denominator, there is no horizontal asymptote; instead, an oblique/slant asymptote may exist.
Applying these rules to the specific function yields the horizontal asymptote.
Conclusion
This paper provides a detailed walkthrough of each problem, illustrating critical methods such as cost comparison analysis, application of the Intermediate Value Theorem, polynomial root-finding techniques, and asymptote calculations. Through systematic approaches and algebraic manipulations, each problem showcases foundational concepts in algebra and calculus essential for understanding function behavior and solving equations accurately. Mastery of these strategies ensures a robust understanding of the topics covered in the quiz.
References
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