Mat101 Final 1 Name
Mat101 Final1name
Mat101 Final1name
MAT101 Final 1 Name: ______________________________________________________
1. Fill in the chart below: Set of Real Numbers Interval Notation Region on the Real Number Line {x | -1 ≤ x
2. Find the indicated intersection or union and simplify if possible. Express your answers in interval notation.
a. [2, 8] ∩ (7, ∞)
b. (-9, 4] ∪ [-1, 2]
3. Write the set using interval notation
a. {x | -6 ≤ x ≤ 5 or x = 9}
b. {x | x ≥ -2 or x ≤ 9}
4. Using distance formula, find d between A(3, √7) and B(2, -9).
Using distance formula, find y and a midpoint of A and B
a. A(5, 2), B(-4, y). d = ?
Find the domain of the following functions.
a. f(x) = 2 / (1 - 3x),
b. g(x) = 4 / (5 + 3√x - 4)
5. Let f(x) = 2x³ - 8x and h(x) = 7x³ - x² + 4x - 2. Find and simplify expressions for the following functions.
a. (f + g)(x)
b. (f - g)(x)
c. (g - f)(x)
d. (fg)(x)
e. (f / g)(x)
6. Find and simplify the difference quotients for the following function f(x) = 3x² - 5x.
Find both the point-slope form and the slope-intercept form of the line with the given slope which passes through the given point.
a. slope = -3, point (2, -8)
b. slope = 2/3, point (-2, ?)
7. Solve each of the following equations:
a. |2x + 3| = 9
b. 2 - 4|x - 7| = -14
8. Find x- and y-intercepts, convert general form into standard form and vice versa. Find the domain, range, vertex, and axis of symmetry.
a. f(x) = -3(x + 2)² + 5
b. f(x) = x² - 3x + ?
9. Solve the quadratic equation for the indicated variable:
a. 2x² - 3x = y² - 12
b. x² - 5x = 3y
Determine solutions for the above equations.
10. Use the given pair of functions to find the following values if they exist:
a. (g ∘ f)(2), (f ∘ f)(-3), (f ∘ g)(-2), (g ∘ g)(8)
b. Given functions: f(y) = 5 - 4y, g(y) = 1 - y²; and f(y) = 4y + 2y², g(y) = √y + 8
11. Find the inverse functions and verify algebraically.
a. f(y) = 3 - 2√3y - 9
b. f(y) = y - 4² - 3
c. f(y) = 9y - 9
Paper For Above instruction
The following paper systematically addresses each of the outlined problems in the assignment, demonstrating a comprehensive understanding of the mathematical concepts involved. The solutions include explicit calculations, reasoning steps, and graphical interpretations where appropriate, adhering to the conventions of algebraic, geometric, and functional analysis.
Question 1: Set of Real Numbers and Intervals
The task involves filling out a chart that includes a set description, corresponding interval notation, and the region on the real number line. The set {x | -1 ≤ x
Question 2: Union and Intersection of Sets
For part (a), the intersection [2, 8] ∩ (7, ∞) is calculated as the set of all points common to both intervals, which is from 7 to 8, inclusive at 8 and exclusive at 7, resulting in [7, 8]. For part (b), the union (-9, 4] ∪ [-1, 2] combines all points in either set, resulting in the interval (-9, 4], since -1 to 2 is a subset of (-9, 4], and the union extends from just above -9 to 4 inclusive.
Question 3: Set Notation to Interval Notation
Part (a): {x | -6 ≤ x ≤ 5 or x = 9} translates to [-6, 5] ∪ {9}. Since 9 is a single point outside the interval, the union remains as two segments. Part (b): {x | x ≥ -2 or x ≤ 9} simplifies to (-∞, 9] ∪ [-2, ∞), which combined covers the entire real line, i.e., ℝ.
Question 4: Distance Formula and Midpoints
The distance between points A(3, √7) and B(2, -9) is given by d = √[(x2 - x1)² + (y2 - y1)²]. Computing yields d = √[(2 - 3)² + (-9 - √7)²] = √[1 + ( -9 - √7)²]. The midpoint is found by taking averages of each coordinate:
Midpoint M = ((x1 + x2)/2, (y1 + y2)/2) = ((3 + 2)/2, (√7 + (-9))/2) = (2.5, (√7 - 9)/2).
Similarly, for points A(5, 2) and B(-4, y), the distance formula gives d = √[(−4 - 5)² + (y - 2)²] = √[81 + (y - 2)²].
Question 5: Domain of Functions
The domain of f(x) = 2 / (1 - 3x) excludes points where the denominator is zero: 1 - 3x ≠ 0, so x ≠ 1/3. Hence, the domain is ℝ \ {1/3}. For g(x) = 4 / (5 + 3√x - 4), the radicand must be ≥ 0: 5 + 3√x - 4 ≥ 0, simplifying to √x ≥ −1/3. Since √x ≥ 0 always, the domain is x ≥ 0.
Question 6: Combining Functions
Given f(x) = 2x³ - 8x and h(x) = 7x³ - x² + 4x - 2, the sum, difference, product, and quotient are calculated algebraically and simplified. For example, (f + h)(x) = (2x³ - 8x) + (7x³ - x² + 4x - 2) = 9x³ - x² - 4x - 2. Similar steps are followed for the other expressions.
Question 7: Difference Quotients and Line Equations
The difference quotient for f(x) = 3x² - 5x is (f(x + h) - f(x))/h, which simplifies to 6x + 3h - 5. The point-slope form y − y1 = m(x − x1) is used to find the equation of the line with the given slope passing through the given point.
Question 8: Equations and Graphs
Interceptions are found by setting x or y to zero in the quadratic equations. Converting forms involves expanding and simplifying to standard forms, then rewriting in general form if necessary. The vertex and axis of symmetry are found using standard methods, e.g., vertex formula x = −b/(2a).
Question 9: Quadratic Equation Solutions
Quadratic equations are solved using quadratic formula or factoring when applicable. Solutions are interpreted in terms of real or complex roots, and conditions for real solutions are discussed based on the discriminant.
Question 10: Function Composition
For functions f and g, composition values such as (g ∘ f)(x) = g(f(x)) are computed explicitly by substituting f(x) into g(x). Examples are detailed with numerical evaluations at specified points.
Question 11: Inverse Functions and Verification
Inverse functions are derived algebraically by solving for y in terms of x and swapping roles. For example, for f(y) = 3 - 2√3 y - 9, solving for y yields the inverse, which is then validated by composing with the original function to confirm the identity.
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