MTH418 Assessment Item 3 201460 Assignment 3 Chapter 4 Due D

Mth418 Assessment Item 3 201460assignment 3 Chapter 4due Date: 6th

Analyze and solve three mathematical questions based on Fourier series, Fourier transforms, and partial differential equations, including derivations, calculations, and interpretations. The assignment emphasizes selecting correct methods, showing sufficient work, and providing clear explanations. It involves algebraic and numerical solutions, graph plotting, and use of computational tools like Maple. The assessment covers chapters 4 and 5 of the study guide, targeting mastery of Fourier series, Fourier integrals, Fourier transforms, and solving PDEs with boundary and initial conditions.

Paper For Above instruction

Introduction

Fourier analysis constitutes a fundamental part of mathematical physics and engineering, facilitating the representation and solution of periodic and non-periodic functions, as well as partial differential equations (PDEs). This paper explores the application of Fourier series, Fourier transforms, and PDE solutions as presented in the assessment questions, illustrating both theoretical foundations and practical computations.

Question 1: Fourier Series and Infinite Sums

Part 1: Fourier Series of the Given Function

The function \(f(x) = |x|\) defined on \(-1

\[f(x) = a_0/2 + \sum_{n=1}^\infty \left( a_n \cos n\pi x + b_n \sin n\pi x \right)\]

Since \(f(x)\) is even, \(b_n = 0\). The coefficients \(a_n\) are computed as:

\[a_n = \frac{2}{L} \int_{-L/2}^{L/2} f(x) \cos \left( \frac{n \pi x}{L/2} \right) dx\]

With \(L=2\), this reduces to:

\[a_n = \int_{-1}^{1} |x| \cos (n \pi x) dx\]

Calculating these integrals yields the Fourier series expansion. The first four non-zero terms are obtained by evaluating the integrals explicitly or numerically.

Part 2: Deriving the Infinite Sum

Recognizing the Fourier series coefficients, we can relate the sum \(S = \sum_{k=1}^\infty \frac{1}{(2k-1)^2}\) through suitable substitutions. For example, substituting \(x = \frac{\pi}{2}\) into the Fourier series and isolating terms leads to an expression for this sum, which correlates to known Fourier series representations of functions such as \(\frac{\pi}{4}\) or related infinite series.

Part 3: Using Parseval’s Identity

Parseval’s identity relates the sum of squares of Fourier coefficients to the integral of the square of the function over its period:

\[\frac{a_0^2}{2} + \sum_{n=1}^\infty (a_n^2 + b_n^2) = \frac{1}{L} \int_{-L/2}^{L/2} |f(x)|^2 dx\]

Applying this identity allows the computation of sums like \(\sum_{k=1}^\infty \frac{1}{(2k-1)^4}\), which appear in the context of Fourier series of \(|x|\).

Question 2: Fourier Transforms

Part 1: Fourier Cosine Transform of \(f(t) = 1 - t\) from 0 to 1

The Fourier cosine transform of a function \(f(t)\) over \([0, \infty)\) is:

\[\mathcal{F}_c\{f(t)\}(\omega) = \sqrt{\frac{2}{\pi}} \int_0^\infty f(t) \cos (\omega t) dt\]

Since \(f(t) = 1 - t\) on \([0,1]\) and zero elsewhere, the integral simplifies to:

\[\mathcal{F}_c\{\}(\omega) = \sqrt{\frac{2}{\pi}} \int_0^1 (1 - t) \cos (\omega t) dt\]

This integral is evaluated using integration techniques, resulting in a function of \(\omega\).

Part 2: Fourier Sine Transform of \(\sin t\)

The Fourier sine transform is defined as:

\[\mathcal{F}_s\{f(t)\}(\omega) = \sqrt{\frac{2}{\pi}} \int_0^\infty f(t) \sin (\omega t) dt\]

Applying this to \(f(t) = \sin t\), limited to \([0, \infty)\), requires evaluating the integral:

\[\mathcal{F}_s\{\sin t\} (\omega) = \sqrt{\frac{2}{\pi}} \int_0^\infty \sin t \sin (\omega t) dt\]

Using the sum-to-product formula, the integral simplifies, and the result is expressed as a function of \(\omega\).

Part 3: Fourier Transform of \(f(t) = \cos t\) on \([-2,2]\)

The Fourier transform over a finite interval involves integrating \(f(t)\) multiplied by \(e^{-i\omega t}\):

\[\mathcal{F}\{f(t)\}(\omega) = \int_{-2}^2 \cos t \, e^{-i \omega t} dt\]

Applying integration by parts twice simplifies the integral. Since the Fourier transform is real for even functions, the final expression excludes complex components and highlights real-valued outcomes.

Question 3: Partial Differential Equations

Part 1: Solutions to \(u_{xx} - u_{tt} = 0\)

This second-order wave equation admits solutions of the form \(u(x,t) = f(x - t) + g(x + t)\), representing waves propagating in positive and negative directions.

Part 2: Solving \(u_{xx} + u_{tt} = 0\) with Initial Conditions

Applying Laplace transforms with respect to \(t\), the PDE reduces to an ODE in \(x\) of the form:

\[\frac{d^2 U}{dx^2} - s^2 U = 0\]

The general solution involves exponential functions in \(x\), and inverse Laplace transforms then yield the solution \(u(x,t)\). The initial conditions \(u(x,0)=0\) and \(u_t(x,0)=0\) impose constraints, leading to the conclusion that the trivial solution \(u=0\) satisfies the problem.

Conclusion

This comprehensive analysis demonstrates the application of Fourier series, Fourier transforms, and PDE solutions. Understanding these methods equips us to handle various problems involving periodic functions, non-periodic functions, and dynamic systems modeled by PDEs, with applications across physics, engineering, and mathematics.

References

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