Question 1: Independent Random Samples Taken On Two Universi
Question 1independent Random Samples Taken On Two University Campuses
Question 1independent Random Samples Taken On Two University Campuses
Question 1 Independent random samples taken on two university campuses revealed the following information concerning the average amount of money spent on non-textbook purchases at the university’s bookstore during the fall semester. University A University B Sample Size Average Purchase $260 $250 Population Standard Deviation(σ) $20 $23 We want to determine if, on the average, students at University A spent more on non-textbook purchases at the university’s bookstore than the students at University B. a. Compute the test statistic. b. Compute the p -value. c. What is your conclusion? Let α = .05.
Paper For Above instruction
The problem involves comparing the means of two independent samples to determine whether students at University A spend more on non-textbook purchases than students at University B during the fall semester. Given the sample sizes, means, and population standard deviations, we analyze using a two-sample z-test for the difference of means.
Data provided includes:
- University A: mean = $260, standard deviation = $20, sample size is not specified but implied to be sufficiently large.
- University B: mean = $250, standard deviation = $23, same considerations as above.
The null hypothesis (H₀) states that there is no difference in average expenditures between students at the two universities, i.e., μ₁ = μ₂. The alternative hypothesis (H₁) suggests that students at University A spend more, i.e., μ₁ > μ₂.
To compute the test statistic, we utilize the z-test formula for independent samples with known population standard deviations:
z = (x̄₁ - x̄₂) / √(σ₁²/n₁ + σ₂²/n₂)
Assuming the sample sizes are large enough, the z-test applies. Given the far-reaching context, as specific sample sizes are not stated, we proceed with typical calculations, assuming equal or sufficiently large sizes for the Central Limit Theorem to hold.
Calculating the z-statistic:
- Difference in means: 260 - 250 = 10
- Standard error: √(20²/n + 23²/n). Without explicit n, but assuming large equal sizes, standard error approximates to √(20²/n + 23²/n) = √((400 + 529)/n) = √(929/n)
For illustration, if we consider n=30 (a common benchmark for large samples), then standard error = √(929/30) ≈ √(30.97) ≈ 5.56.
Then the z-statistic is:
- z = 10 / 5.56 ≈ 1.8
We then determine the p-value associated with this z-score for a one-tailed test (since the hypothesis indicates that μ₁ > μ₂). Consulting standard normal distribution tables, a z-value of 1.8 corresponds to a p-value of approximately 0.0359.
Since the p-value (0.0359) is less than the significance level α=0.05, we reject the null hypothesis. Therefore, there is statistically significant evidence at the 5% level to conclude that students at University A spend more on non-textbook purchases than students at University B during the fall semester.
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