Quiz 21: Once Upon A Time I Had A Fast Food Lunch
Quiz 21 10 Points Once Upon A Time I Had A Fast Food Lunch With A
Once upon a time, I had a fast-food lunch with a mathematician colleague. I noticed a very strange behavior in him. I called it the Au-Burger Syndrome since it was discovered by me at a burger joint. Based on my unscientific survey, it is a rare but real malady inflicting 2% of mathematicians worldwide. Yours truly has recently discovered a screening test for this rare malady, and the finding has just been reported to the International Association of Insane Scientists (IAIS) for publication.
Unfortunately, my esteemed colleagues who reviewed my submitted draft discovered that the reliability of this screening test is only 80%. What it means is that it gives a positive result, false positive, in 20% of the mathematicians tested even though they are not afflicted by this horribly-embarrassing malady. I have found an unsuspecting victim, oops, I mean subject, down the street. This good old mathematician is tested positive! What is the probability that he is actually inflicted by this rare disabling malady?
Paper For Above instruction
The problem described involves applying Bayes’ theorem to determine the probability that a mathematician who tests positive for the Au-Burger Syndrome actually has the malady. Given the data: a prevalence (prior probability) of 2% (0.02), a test sensitivity (true positive rate) of 80% (0.80), and a false positive rate of 20% (meaning that the test incorrectly indicates the malady in 20% of healthy individuals), the goal is to find the posterior probability that the individual is truly afflicted given a positive test result.
Applying Bayes’ theorem, the probability that the mathematician is actually afflicted given a positive test is:
P(afflicted | positive) = [P(positive | afflicted) * P(afflicted)] / P(positive)
Where P(positive) = P(positive | afflicted) P(afflicted) + P(positive | not afflicted) P(not afflicted)
Substituting the known values:
- P(afflicted) = 0.02
- P(not afflicted) = 1 - 0.02 = 0.98
- P(positive | afflicted) = 0.80
- P(positive | not afflicted) = 0.20
Calculating P(positive):
P(positive) = (0.80)(0.02) + (0.20)(0.98) = 0.016 + 0.196 = 0.212
Finally, calculating the posterior probability:
P(afflicted | positive) = 0.016 / 0.212 ≈ 0.0755 or 7.55%
This means that even though the mathematician tests positive, there is only about a 7.55% chance that he actually has the Au-Burger Syndrome. This illustrates the importance of considering both the test's reliability and the prior prevalence when interpreting medical or diagnostic test results.
Another Perspective on Bayesian Inference
This example underscores a common misconception about diagnostic tests: a positive result does not necessarily mean a high probability of the disease's presence. Given the low prevalence (2%) and imperfect test accuracy, most positive tests are false positives, which significantly lowers the actual probability of being truly afflicted. In clinical practice, this highlights the importance of confirmatory testing, especially for low-prevalence conditions.
In conclusion, the probability that a mathematician who tests positive for the Au-Burger Syndrome truly has it is approximately 7.55%, emphasizing the need for cautious interpretation of screening results and the utility of Bayesian analysis in diagnostic decision-making.
References
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- Bishop, C. M. (2006). Pattern Recognition and Machine Learning. Springer.
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