Solve The Problem: Auditorium Has 25 Rows With 10 Seats
Solve The Probleman Auditorium Has 25 Rows With 10 Seats In The First
Identify the core assignment: solve a set of math problems including counting seats in an auditorium with increasing seats per row, calculating weights of fruit salad, analyzing survey data, summing an arithmetic sequence, converting numbers between bases, defining sets from a Cartesian product, examining functions and relations, and converting numerals between numeral systems.
Paper For Above instruction
The collection of problems presented encompasses various mathematical and logical concepts, ranging from basic arithmetic computations to advanced set theory and numeral system conversions, all reflecting fundamental skills necessary for mastering mathematics at an intermediate to advanced level.
Seats in the Auditorium
The problem describes an auditorium with 25 rows, where the first row contains 10 seats, the second contains 12, the third 14, and so on, increasing by 2 seats per row. To determine the total number of seats, we recognize this as an arithmetic sequence with the initial term (a₁) equal to 10, a common difference (d) of 2, and the number of terms (n) equal to 25. The number of seats in each row for row i can be expressed as:
aₙ = a₁ + (n - 1)d
Thus, the seats in the last (25th) row are:
a₂₅ = 10 + (25 - 1) × 2 = 10 + 48 = 58
The total number of seats (Sₙ) in all 25 rows is the sum of an arithmetic series:
Sₙ = (n/2)(a₁ + aₙ) = (25/2)(10 + 58) = (25/2)(68) = 25 × 34 = 850
Therefore, the total number of seats in the auditorium is 850.
Fruit Salad Composition
A fruit salad weighing 75 ounces contains cantaloupe, strawberries, and bananas. The salad contains three ounces of bananas for every ounce of strawberries, and it has equal ounces of cantaloupe and strawberries. Let’s define variables:
- Let s = ounces of strawberries
- Since there are the same ounces of cantaloupe, melon = s
- Bananas = 3 × s
The total weight equation becomes:
s (strawberries) + s (cantaloupe) + 3s (bananas) = 75
Combine like terms:
5s = 75
s = 15
Thus, strawberries = 15 ounces, cantaloupe = 15 ounces, and bananas = 3 × 15 = 45 ounces.
The salad contains 45 ounces of bananas.
Survey Data Analysis
Out of fifty students, 30 like red jelly beans, and 29 like green jelly beans, with 17 liking both. To find students who like neither, we use the principle of inclusion-exclusion:
Number liking red or green:
|R ∪ G| = |R| + |G| - |R ∩ G| = 30 + 29 - 17 = 42
Number liking neither:
n(N) = total students - students liking red or green = 50 - 42 = 8
Therefore, 8 students like neither red nor green jelly beans.
Sum of Arithmetic Sequence
The sequence 4 + 8 + 12 + ... + 500 is arithmetic with first term a₁=4, common difference d=4, and last term aₙ=500.
Number of terms n:
aₙ = a₁ + (n - 1)d
500 = 4 + (n - 1) × 4
(n - 1) × 4 = 496
n - 1 = 124
n = 125
Sum of the sequence:
Sₙ = (n/2)(a₁ + aₙ) = (125/2)(4 + 500) = (125/2)(504) = 125 × 252 = 31,500
The sum of the arithmetic sequence is 31,500.
Number Base Conversion
Converting 2874 (base ten) to base five:
Divide repeatedly by 5:
- 2874 ÷ 5 = 574 remainder 4
- 574 ÷ 5 = 114 remainder 4
- 114 ÷ 5 = 22 remainder 4
- 22 ÷ 5 = 4 remainder 2
- 4 ÷ 5 = 0 remainder 4
Reading remainders from last to first, 2874 in base five is: 42444.
Number Base 200
The numeral '200' in base ten can be expressed in base X. To find the base where '200' in base X equals a certain value, further specifications are needed. Since the problem asks to 'write the numeral base 200 six,' it seems to be a prompt for a numeral conversion or notation, but lacks clarity. If interpreting '200' as decimal and converting to another base, the context would clarify the specific base.
Cartesian Product Sets
Given the Cartesian product A* B with pairs {(a,p), (a,q), (a,r), (b,p), (b,q), (b,r)}, the sets A and B are determined by these pairs:
- A contains the first elements: A = {a, b}
- B contains the second elements: B = {p, q, r}
One-to-One Correspondence
It is not possible to establish a one-to-one correspondence between the set {4, 2, 9, 5} and {-4, 2, -9, 5} because the sets have different elements and possibly different cardinalities, and the elements do not map uniquely. For a bijection, each element must be paired uniquely, but negative counterparts indicate the sets are not in a one-to-one correspondence.
Function Analysis
The set of ordered pairs {(animal, zebra), (bird, parrot), (flower, rose), (tree, elm)} defines a relation. To determine if it is a function, each input (first element) must have exactly one output (second element). All the first elements are unique: animal, bird, flower, tree, with respective outputs. Since each input uniquely maps to a single output, this relation qualifies as a function.
Numeral Conversion: Hindu-Arabic to Babylonian and Egyptian
Given the numeral 210 in Hindu-Arabic numeral system:
- Babylonian: The Babylonian numeral system is base-60. Conversion involves dividing 210 by 60:
210 ÷ 60 = 3 remainder 30, thus 210 in Babylonian is '3;30'.
- Egyptian: The Egyptian numeral system uses hieroglyphs representing powers of ten, but here '11000' suggests a symbolic form, which typically means 1, 1, 0, 0, 0, or perhaps a notation indicating a numeral in the Egyptian system. Without detailed hieroglyphic notation, it suffices to state that the number 11000 in Egyptian notation would be represented as a sequence of symbols for 10,000, 1,000, etc., but further clarification is needed for precise representation.
Conclusion
The aforementioned problems demonstrate application of fundamental mathematical principles, including arithmetic series, set theory, number conversions, and analysis of relations, which are crucial for advanced mathematical comprehension and problem-solving proficiency.
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