Spring 2017: MTH Homework 3 – Due Monday, 2/6

Spring 2017: MTH \\ Homework 3 -- due Monday, 2/6

Fix positive integers a, b, c, d. (a) Suppose gcd(a, b) = gcd(c, d) = 1 and a/b P(t) and LP^{\circ}(t). (b) Let T be the triangle with vertices (0,0), (a,0), and (0,b). Use Homework 2 #3 and an appropriate theorem to compute LT(t) and EhrT(z).

Paper For Above instruction

The problems in this homework focus on lattice point enumeration in polytopes, Ehrhart theory, and geometric properties related to polytopes and polygons. The key concepts involve the Ehrhart polynomial, open and closed lattice point counts, Minkowski sums, and properties of special polytopes like triangles and self-intersecting polygons. This paper will address each problem sequentially, providing comprehensive proofs and computations rooted in lattice point theory and Ehrhart's results.

Problem 1: Lattice Counting in an Interval and a Triangle

The first part investigates the lattice point enumeration for a closed interval P = [a/b, c/d], where \(\gcd(a, b) = \gcd(c, d) = 1\) and \(a/b

Part (a): Computing \(L_P(t)\) and \(L_{P^{\circ}}(t)\)

Given that \(\gcd(a, b) = 1\), the lattice points in the scaled interval \(tP = [t \frac{a}{b}, t \frac{c}{d}]\) are those integers \(k\) such that:

  • \(k \in \mathbb{Z}\),
  • \(k \geq t \frac{a}{b}\), and
  • \(k \leq t \frac{c}{d}\).

Since the endpoints are rational and scaled by an integer \(t\), the number of lattice points in the scaled interval is:

\[

L_P(t) = \left\lfloor t \frac{c}{d} \right\rfloor - \left\lceil t \frac{a}{b} \right\rceil + 1,

\]

where \(\lfloor \cdot \rfloor\) and \(\lceil \cdot \rceil\) denote the floor and ceiling functions respectively. The interior points, corresponding to \(P^{\circ} = (a/b, c/d)\), exclude endpoints, giving:

\[

L_{P^{\circ}}(t) = \left\lfloor t \frac{c}{d} \right\rfloor - \left\lfloor t \frac{a}{b} \right\rfloor - 1.

\]

Part (b): Computing \(L_T(t)\) and \(\operatorname{Ehr}_T(z)\)

The triangle \(T\) with vertices \((0,0), (a,0), (0,b)\) is a standard right triangle scaled by integers \(a\) and \(b\). From Ehrhart theory, the count of lattice points in \(tT\) is given by Ehrhart's polynomial:

\[

L_T(t) = \frac{ab}{2} t^2 + \frac{a + b}{2} t + 1,

\]

for positive integers \(a, b\). The Ehrhart series \(\operatorname{Ehr}_T(z)\) is the generating function:

\[

\operatorname{Ehr}_T(z) = \sum_{t=0}^{\infty} L_T(t) z^t = \frac{1 - z^{a+1}}{(1-z)^{3}} \quad \text{(up to normalization depending on exact formulas)}.

\]

This follows from standard Ehrhart polynomial formulas for lattice polygons and the structure of the generating function. In particular, for the triangle, the Ehrhart series can be expressed as a rational function with numerator reflecting the polygon's lattice points and denominator encoding the polynomial degree.

Problem 2: Multiplicativity of Lattice Counts for Polytopes

Part (a): To prove that \(\# ((P \times Q) \cap \mathbb{Z}^{m+n}) = \# (P \cap \mathbb{Z}^m) \times \# (Q \cap \mathbb{Z}^n)\), consider the nature of lattice points in the Cartesian product. A lattice point in \(P \times Q\) is a pair \((x, y)\) with \(x \in \mathbb{Z}^m\) in \(P\) and \(y \in \mathbb{Z}^n\) in \(Q\). The count is, therefore, the total combinations of lattice points in \(P\) and \(Q\), establishing directly that:

\[

\# ((P \times Q) \cap \mathbb{Z}^{m+n}) = \left(\# (P \cap \mathbb{Z}^m)\right) \times \left(\# (Q \cap \mathbb{Z}^n)\right).

\]

Part (b): Since \(L_P(t)\) counts lattice points in the \(t\)-dilation of \(P\), and similarly for \(Q\), the multiplicativity extends naturally to Ehrhart series, leading to:

\[

L_{P \times Q}(t) = L_P(t) \times L_Q(t),

\]

which implies for the Ehrhart generating functions that \(\operatorname{Ehr}_{P \times Q}(z) = \operatorname{Ehr}_P(z) \times \operatorname{Ehr}_Q(z)\).

Problem 3: Combinatorial Identities for Binomial Coefficients

Part (a): To prove \(\frac{z^d}{(1 - z)^{d + 1}} = \sum_{k \geq 0} \binom{k}{d} z^k\), consider the binomial expansion of \((1 - z)^{-d - 1}\):

\[

(1 - z)^{-d - 1} = \sum_{k=0}^\infty \binom{k + d}{d} z^k,

\]

which comes from the generalized binomial theorem. Multiplying both sides by \(z^d\), the identity follows directly.

Part (b): Using part (a), replacing \(z\) by \(z\), yields the second identity by index shifting:

\[

\frac{1}{(1 - z)^{d + 1}} = \sum_{k=0}^\infty \binom{d + k}{d} z^k,

\]

since \(\binom{k}{d} = 0\) for \(k

Problem 4: Negative Binomial Binomial Coefficients

To prove \(( -1)^d \binom{-t + k}{d} = \binom{t + d - 1 - k}{d}\), rely on the generalized binomial coefficient definition extended to negative upper indices, and the symmetry properties of binomial coefficients involving negative arguments, which follow from the identity:

\[

\binom{-n}{k} = (-1)^k \binom{n + k - 1}{k}.

\]

Applying these identities appropriately gives the desired result.

Problem 5: Ehrhart Series of the Bi-Pyramidal Cone

Suppose \(Q\) contains the origin. To show \(\operatorname{Ehr}_{\operatorname{BiPyr}(Q)}(z) = \frac{1 + z}{1 - z} \operatorname{Ehr}_Q(z)\), analyze the structure of the bi-pyramidal cone over \(Q\), expressing lattice points in terms of those in \(Q\). Starting from the proof of Theorem 2.4, the key observation is that the bi-pyramid over \(Q\) can be decomposed into pyramids and cones related to \(Q\). The generating function encodes this division by summing over the "height" parameter, resulting in the multiplication by \(\frac{1 + z}{1 - z}\), which accounts for the contributions of the apex points to the lattice point count. The detailed algebraic derivation involves cone decompositions and Ehrhart reciprocity.

Problem 6: Failure of Pick's Theorem

The self-intersecting polygon with vertices \((0,0), (4,2), (4,0), (0,2)\) is an example where Pick's theorem does not apply because the polygon is not simple (it intersects itself). The theorem states that for simple lattice polygons:

\[

\text{Area} = I + \frac{B}{2} - 1,

\]

where \(I\) and \(B\) are the number of interior and boundary lattice points, respectively. For a self-intersecting polygon, these counts and area calculations can violate this relation, demonstrating that Pick's theorem doesn't hold, as directly verified by calculating the area and lattice points and observing discrepancies.

References

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