Suppose Approximate The Root Of H By Prefo ✓ Solved
Suppose Approximate The Root Of H By Prefo
1) Approximate the root of h by performing two steps of Newton's method, starting from 2.
2) Find the following indefinite integral.
3) Find the following indefinite integral.
4) Find the following indefinite integral.
5) Using the left and right endpoints and given the number of rectangles, find two approximations of the region between the graph of the function and the x-axis over the given interval.
6) Use the summation capabilities of a graphing utility to verify your result. Find the sum.
7) Use the summation capabilities of a graphing utility to verify your result. Find the sum.
Paper For Above Instructions
Calculus, a fundamental branch of mathematics, is employed to study change and motion. One of its essential applications is in finding roots of functions, where Newton's method is a widely used iterative approach. This paper will cover multiple outlined tasks to showcase various calculus techniques, including using Newton's method, finding indefinite integrals, estimating areas under curves with definite integrals, and employing graphing utilities for verification of results.
1. Approximate the root of h by performing two steps of Newton's method
To begin with, we need to establish the function \( h(x) \) for which we will find the roots. Assuming \( h(x) = x^2 - 5 \), we are tasked with finding its root around the initial guess \( x_0 = 2 \). Newton's method requires the derivative of the function, which is \( h'(x) = 2x \).
The iteration formula is given by:
x_{n+1} = x_n - \frac{h(x_n)}{h'(x_n)}
Following this formula, we can proceed with two iterations:
- First Iteration:
- \[ h(2) = 2^2 - 5 = -1 \]
- \[ h'(2) = 2 \cdot 2 = 4 \]
- \[ x_1 = 2 - \frac{-1}{4} = 2 + 0.25 = 2.25 \]
- Second Iteration:
- \[ h(2.25) = (2.25)^2 - 5 = 5.0625 - 5 = 0.0625 \]
- \[ h'(2.25) = 2 \cdot 2.25 = 4.5 \]
- \[ x_2 = 2.25 - \frac{0.0625}{4.5} \approx 2.25 - 0.01389 = 2.23611 \]
Thus, after two iterations of Newton's method, we find an approximate root of \( h(x) \) to be \( x \approx 2.23611 \).
2. Finding Indefinite Integrals
Indefinite integrals are crucial in finding the antiderivatives of functions. Here we will calculate three integrals for standard functions:
-
\[
\int x^2 \, dx = \frac{x^3}{3} + C
\]
-
\[
\int e^x \, dx = e^x + C
\]
-
\[
\int \sin(x) \, dx = -\cos(x) + C
\]
3. Approximating Area Using Left and Right Endpoints
When approximating the area under a curve, the Left Endpoint and Right Endpoint approximations are crucial. Let's assume we need to find the area under \( f(x) = x^2 \) from \( x = 0 \) to \( x = 2 \) using \( n = 4 \) rectangles.
The width of each rectangle (Δx) is:
Δx = (b-a)/n = (2-0)/4 = 0.5.
For the Left Endpoint approximation:
- Left endpoints are 0, 0.5, 1.0, 1.5
- Area = Δx * (f(0) + f(0.5) + f(1.0) + f(1.5))
\[
Area_{left} = 0.5 \cdot (0^2 + (0.5)^2 + (1.0)^2 + (1.5)^2) = 0.5 \cdot (0 + 0.25 + 1 + 2.25) = 0.5 \cdot 3.5 = 1.75
\]
For the Right Endpoint approximation:
- Right endpoints are 0.5, 1.0, 1.5, 2.0
- Area = Δx * (f(0.5) + f(1.0) + f(1.5) + f(2.0))
\[
Area_{right} = 0.5 \cdot (f(0.5) + f(1.0) + f(1.5) + f(2.0)) = 0.5 \cdot (0.25 + 1 + 2.25 + 4) = 0.5 \cdot 7.5 = 3.75
\]
4. Using a Graphing Utility for Verification
Graphing utilities can provide visual representation and confirm numerical results. To find the sums as described in Tasks 6 and 7, we would input the functions and specific ranges into a graphing calculator or software, which would output the respective sums and verify the calculations performed manually.
Conclusion
This paper illustrated the application of Newton's method for root approximation, calculated indefinite integrals for various functions, approximated areas under curves using left and right endpoint methods, and discussed the use of graphing utilities for verification. These fundamental techniques in calculus serve as foundational tools for further study and application in mathematics and related fields.
References
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