Suppose X Is A Uniform Random Variable With A = -5 And B = 2
Suppose X is a uniform random variable with a = -5 and b = 25
Suppose X is a uniform random variable with a = -5 and b = 25. Fill in the blanks. The mean of X is 10. The variance of X is 100. The standard deviation of X is 10.0000. Fill in the blank. (Round your answers to two decimal places.) P(-10<X<-1) is 0.36. Fill in the blank. (Round your answers to two decimal places.) P(X>0) is 0.60. P(X≥0) is 0.60. Fill in the blank P(X≥20|X≥10) is 0.50.
Paper For Above instruction
The given problem involves analyzing a uniform random variable, X, with specified parameters a = -5 and b = 25. Several statistical properties and probabilities related to this uniform distribution are to be calculated, followed by an extensive analysis using real-world data from colleges and universities to assess relationships among various financial and demographic variables.
First, for the uniform distribution, the mean (expected value) is calculated as (a + b) / 2. Substituting the values yields (−5 + 25) / 2 = 20 / 2 = 10. This confirms that the average value of the variable X is 10.
Next, the variance of a uniform distribution is given by ((b − a)^2) / 12. Computing this with our parameters: ((25 − (−5))^2) / 12 = (30^2) / 12 = 900 / 12 = 75. Notably, earlier it was mentioned as 100, which is mathematically inconsistent with the standard variance formula for a uniform distribution. Therefore, the correct variance is 75, not 100.
The standard deviation is the square root of the variance: √75 ≈ 8.6603, which we round to four decimal places as 8.6603. The earlier statement of 10.0000 appears incorrect based on mathematical calculations.
Moving to probability calculations, for P(−10 < X < −1), the uniform distribution spans from −5 to 25. The probability that X falls between −10 and −1 involves the segment from max(−10, −5) = −5 to −1. The length of this interval is (−1) − (−5) = 4. The total length of the distribution is (25 − (−5)) = 30. Therefore, the probability is the interval length over the total: 4 / 30 ≈ 0.1333. However, since the interval starts from −10 (which is outside our distribution starting at −5), the actual lower limit for the probability is −5, so the interval is from −5 to −1, length 4, resulting in a probability of 4 / 30 ≈ 0.1333. The initial estimate of 0.36 seems inconsistent and thus likely incorrect based on this calculation.
Similarly, P(X > 0) is calculated as the proportion of the distribution greater than 0. The interval from 0 to 25 has length 25, and the total length is 30, so P(X > 0) = 25 / 30 ≈ 0.8333. Conversely, P(X ≥ 0) is the same, approximately 0.8333.
The conditional probability P(X ≥ 20 | X ≥ 10) can be derived by noting that for a uniform distribution, the conditional probability equals the proportion of the interval [20, 25] over [10, 25]. The interval from 20 to 25 has length 5, and from 10 to 25 has length 15. Therefore, P(X ≥ 20 | X ≥ 10) = 5 / 15 = 1 / 3 ≈ 0.3333.
Beyond these probabilistic calculations, the assignment also involves analyzing data from colleges and universities, specifically examining correlations among variables such as Endow, AvgFinAid, Tuition, RmBrd, and %FinAid, and conducting regression analysis to understand the predictors of Tuition for private colleges/universities.
The correlation analysis would involve computing Pearson's correlation coefficients between these variables. Expect that variables like Endow and Tuition might have a positive correlation, indicating that wealthier institutions tend to have higher tuition. Conversely, %FinAid may be negatively correlated with Tuition, implying that higher financial aid percentages could be associated with lower tuition in some contexts. The correlation table and its interpretation would establish which relationships are statistically significant and meaningful.
In investigating the impact of %FinAid, AvgFinAid, and Region on Tuition for private colleges, regression analysis is essential. The model predicts Tuition based on these predictors, with the hypothesis that higher %FinAid and AvgFinAid might reduce Tuition, while Region could also significantly influence tuition levels, reflecting geographic disparities.
The regression results, including coefficients, significance levels, R-squared, and assumptions testing (such as residual plots for homoscedasticity and normality), help determine the strength and validity of the model. The regression coefficients quantify the expected change in Tuition for each unit change in the predictors, enabling interpretability for decision-makers. The standard deviation of the regression, often called the root mean square error, indicates how much observed Tuition values deviate, on average, from those predicted by the model.
The R-squared value measures the proportion of variability in Tuition explained by the model, with higher values indicating a better fit. A detailed calculation involves the regression sum of squares divided by the total sum of squares, which can be derived from the analysis output data.
Finally, the adequacy of the model assumptions—linearity, independence, normality, and homoscedasticity—must be assessed through residual plots and other diagnostic tests. Proper validation ensures that the inferences drawn are reliable. Based on the analyses, conclusions highlight the significance and strength of relationships among variables and their implications for university financial strategies and policy decisions.
In summary, the statistical analyses reveal key insights into the financial dimensions of higher education institutions, with implications for administrators and policymakers aiming to optimize financial aid strategies, tuition pricing, and resource allocation. The findings underscore the importance of considering geographic, financial, and institutional factors when developing strategies to increase accessibility and financial sustainability in higher education.
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