The Following Mass And Volume Data Is Given In The Sequence

The Following Mass And Volume Data Is Given In The Sequnce In Which It

The following mass and volume data is given in the sequence in which it was obtained: 1) mass of beaker, empty tube: 29.661 g; 2) beginning liquid level: 17.13 mL; 3) ending liquid level: 29.75 mL; 4) mass of beaker, tube, and transferred copper sulfate solution: 50.031 g. Enter this data in the table and determine the volume and mass of copper sulfate solution transferred. Include units and report results to the correct number of significant figures. Volume Tube V_f .................... V_i .................... V_t .................... Mass m_{tube+beaker+solution} .......................... m_tube+beaker ...................... m_solution ............................

Paper For Above instruction

The experiment involves calculating the transferred volume and mass of copper sulfate solution, based on given measurements. The process starts with understanding the data points provided: the initial and final liquid levels in the container, and the masses of the apparatus with and without the solution. These measurements are essential to accurately determine the volume of solution transferred, as well as its mass.

Firstly, the initial and final liquid levels are used to compute the volume of copper sulfate solution transferred during the experiment. The initial volume (V_i) is 17.13 mL, and the final volume (V_f) is 29.75 mL. The change in volume, V_t, represents the volume of solution transferred. This is calculated as:

V_t = V_f - V_i = 29.75 mL - 17.13 mL = 12.62 mL

This volume is reported to four significant figures, consistent with the least precise measurement provided.

Next, the mass of the copper sulfate solution transferred is determined by subtracting the mass of the empty apparatus from the mass after transfer. The mass of the beaker and tube alone (m_tube+beaker) is calculated by subtracting the mass of the beaker alone from the combined mass with the solution after transfer. Since the mass of the beaker alone isn't provided, the total mass of beaker, tube, and solution (50.031 g) should be compared with the mass of the empty tube and beaker (29.661 g). The difference gives the mass of the solution transferred:

m_solution = (m_{tube+beaker+solution}) - (mass of beaker and tube alone) = 50.031 g - 29.661 g = 20.370 g

However, since the initial mass of the beaker and tube without solution is given as 29.661 g, the mass of the solution transferred is 20.370 g, reported to five significant figures. This measurement indicates the mass of copper sulfate solution transferred during the experiment.

These calculations demonstrate the correlation between volume and mass in solution measurements, which is critical in analytical chemistry to determine concentration and other properties. Accurate measurements and reporting significant figures ensure the validity and reproducibility of results.

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