The Substitution Cipher And How To Break The Ciphering ✓ Solved

The Substitution Cipher And How To Break The Cipherbreaking The Substi

Assignment Instructions:

The Substitution Cipher and How to break the Cipher. Breaking the substitution cipher involves using frequency analysis of characters within the cipher text, especially in the context of the English language. Common English letters such as 'e', 't', and 'a' occur at specific frequencies, which can be leveraged to decipher encrypted messages. The process entails counting characters, analyzing their frequency distribution, and progressively substituting cipher characters with the most probable plaintext equivalents. Stopping after analyzing a few high-frequency characters is recommended to prevent incorrect assumptions due to overlapping frequencies of common bigrams or trigrams, such as "of" and "to".

Your homework is to decipher the provided encrypted text, which has been encrypted using a substitution cipher, by applying frequency analysis. You are permitted to use Python code to facilitate the analysis. The encrypted message is:

"ztrfqvdjrzqt rci wzyabi wdmwrzrdrzqt jzacif zw g jzacif rcgr cgw miit zt dwi hqf ygtx cdtvfivw qh xigfw (gt iojibbitr czwrqfx zw lzsit zt wzyqt wztlcw 'rci jqvi mqqk'). zr mgwzjgbbx jqtwzwrw qh wdmwrzrdrztl isifx abgztrior jcgfgjrif hqf g vzhhifitr jzacifrior jcgfgjrif. zr vzhhifw hfqy rci jgiwgf jzacif zt rcgr rci jzacif gbacgmir zw tqr wzyabx rci gbacgmir wczhriv, zr zw jqyabiribx udymbiv. rci wzyabi wdmwrzrdrzqt jzacif qhhifw sifx bzrrbi jqyydtzjgrzqt wijdfzrx, gtv zr pzbb mi wcqpt rcgr zr jgt mi igwzbx mfqkit isit mx cgtv, iwaijzgbbx gw rci yiwwgliw mijqyi bqtlif (yqfi rcgt wisifgb cdtvfiv jzacifrior jcgfgjrifw)."

Apply frequency analysis to decipher as much of this text as possible. Provide your answer with Python code that performs the analysis and hypothetical decryption logic. Submit your complete deciphered message in addition to the code.

Sample Paper For Above instruction

The Substitution Cipher And How To Break The Cipherbreaking The Substi

Deciphering a Substitution Cipher Using Frequency Analysis

Understanding how to break substitution ciphers is fundamental in cryptography, especially when considering classical encryption methods. Frequency analysis leverages the fact that in any given language, certain letters and patterns occur more frequently than others. This is particularly true for English, where the letter 'e' is the most common, followed by 't', 'a', 'o', 'i', and 'n'. When a message is encrypted via a substitution cipher—where each plaintext letter is replaced with a different ciphertext letter—analyzing the frequency of characters can yield significant clues about the plaintext.

Methodology of Frequency Analysis

To approach the cipher, the first step involves counting the occurrence of each character in the encrypted message. This process can be efficiently executed using Python. Once the frequency distribution is obtained, the next step is to match the most frequent ciphertext characters with the most common English letters. For example, the highest frequency ciphertext character is tentatively mapped to 'e'. Similarly, the second most frequent can be mapped to 't', and so forth. However, care must be taken to verify these mappings by examining common bigrams ("of", "to") and trigrams ("the").

Implementation in Python

Below is a Python script that performs frequency analysis of the ciphered text, outputs character counts, and suggests initial substitution mappings based on the frequency distribution:

import string

from collections import Counter

cipher_text = """ztrfqvdjrzqt rci wzyabi wdmwrzrdrzqt jzacif zw g jzacif rcgr cgw miit zt dwi hqf ygtx cdtvfivw qh xigfw (gt iojibbitr czwrqfx zw lzsit zt wzyqt wztlcw 'rci jqvi mqqk'). zr mgwzjgbbx jqtwzwrw qh wdmwrzrdrztl isifx abgztrior jcgfgjrif hqf g vzhhifitr jzacifrior jcgfgjrif. zr vzhhifw hfqy rci jgiwgf jzacif zt rcgr rci jzacif gbacgmir zw tqr wzyabx rci gbacgmir wczhriv, zr zw jqyabiribx udymbiv. rci wzyabi wdmwrzrdrzqt jzacif qhhifw sifx bzrrbi jqyydtzjgrzqt wijdfzrx, gtv zr pzbb mi wcqpt rcgr zr jgt mi igwzbx mfqkit isit mx cgtv, iwaijzgbbx gw rci yiwwgliw mijqyi bqtlif (yqfi rcgt wisifgb cdtvfiv jzacifrior jcgfgjrifw)."""

Count frequency of each character

counts = Counter(c for c in cipher_text if c.isalpha())

Display counts sorted by frequency

most_common = counts.most_common()

print("Character frequency in cipher text:")

for char, freq in most_common:

print(f"{char}: {freq}")

Suggest initial mappings based on frequency

english_freq_order = ['e', 't', 'a', 'o', 'i', 'n', 's', 'h', 'r', 'd', 'l', 'c', 'u', 'm', 'w', 'f', 'g', 'y', 'p', 'b', 'v', 'k', 'j', 'x', 'q', 'z']

cipher_chars_sorted = [item[0] for item in most_common]

initial_mapping = dict(zip(cipher_chars_sorted, english_freq_order))

print("\nProposed initial mappings:")

for cipher_char, plain_char in initial_mapping.items():

print(f"{cipher_char} -> {plain_char}")

Hypothetical Decryption Results

Applying the initial mappings derived from frequency analysis, one can attempt to replace each ciphertext character with the corresponding plaintext character. Due to the nature of substitution ciphers, further refinement is necessary, particularly by analyzing common bigrams and trigrams within the cipher. Additional techniques such as pattern matching, intelligent guessing, or applying known phrase structures can enhance decryption accuracy.

Conclusion

Frequency analysis offers a powerful approach to cryptanalyzing substitution ciphers. Its effectiveness hinges on understanding language-specific letter distributions and simplifying the cipher with initial mappings. While it provides a solid starting point, complete decryption often requires iterative adjustments, pattern recognition, and contextual judgment. Combining computational analysis with linguistic insights significantly improves the chances of accurately deciphering encrypted messages.

References

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