Tom, Jan, And Julie Are Majors At Great State University

Question

Tom Jan And Julie Are Is Majors At Great State University These Stu Tom, Jan, and Julie are IS majors at Great State University. These students have been assigned to a class project by one of their professors, requiring them to develop a new Web-based system to collect and unique information on the IS program’s alumni. This system will be used by the IS graduates to enter job and address information as they graduate, and then make changes to that information as they change jobs and/or address. Their professor also has a number of queries that she is interested in being able to implement. Based on their preliminary discussions with their professor, the students have developed this list of system elements: Inputs: 1 low complexity, 2 medium complexity, 1 high complexity. Outputs: 4 medium complexity. Queries: 1 low complexity, 4 medium complexity, 2 high complexity. Files: 3 medium complexity. Program interfaces: 2 medium complexity. Assume that an adjusted project complexity factor of 1.2 is appropriate for this project. Calculate the total adjusted function points for this project.

Dr. Jack HW Helper · Accepted Answer

The calculation of total adjusted function points (FP) for the system described involves several steps, including identifying unadjusted function points based on system elements and then modifying these by an appropriate complexity factor. This process is rooted in the Function Point Analysis (FPA) methodology, a standardized technique for measuring software size based upon the functionality the system provides to the user, regardless of technology or programming language (Albrecht, 1979; IFPUG, 2010). Unadjusted Function Points Calculation The initial step requires classifying the system elements—inputs, outputs, queries, files, and interfaces—as categorized by their complexity levels: low, medium, or high. Each category has predefined weighting values derived from the International Function Point User Group (IFPUG) standards. Inputs - Low complexity: 1 input - Medium complexity: 2 inputs - High complexity: 1 input Using standard weights: - Low complexity input = 3 FP - Medium complexity input = 4 FP - High complexity input = 6 FP Calculating: - Low: 1 × 3 FP = 3 FP - Medium: 2 × 4 FP = 8 FP - High: 1 × 6 FP = 6 FP Total Input FP = 3 + 8 + 6 = 17 FP Outputs - 4 outputs, all medium complexity: - Medium output weight = 5 FP - Total output FP = 4 × 5 FP = 20 FP Queries - 1 low complexity: 3 FP - 4 medium complexity: 4 × 5 FP = 20 FP - 2 high complexity: 2 × 7 FP = 14 FP Total query FP = 3 + 20 + 14 = 37 FP Files - 3 medium complexity files - Medium file weight = 10 FP - Total file FP = 3 × 10 FP = 30 FP Program interfaces - 2 medium complexity interfaces - Medium interface weight = 7 FP - Total interface FP = 2 × 7 FP = 14 FP Total Unadjusted Function Points Adding all system elements: $$ \text{Unadjusted FP} = 17 + 20 + 37 + 30 + 14 = 118 $$ Applying the Complexity Adjustment Factor The system requires an adjustment factor, known as the Value Adjustment Factor (VAF), reflecting the system’s complexity characteristics. Given an adjustment factor of 1.2, the total func

Tom, Jan, And Julie Are Majors At Great State University

Tom Jan And Julie Are Is Majors At Great State University These Stu

Paper For Above instruction

Unadjusted Function Points Calculation

Inputs

Outputs

Queries

Files

Program interfaces

Total Unadjusted Function Points

Applying the Complexity Adjustment Factor

Final Result

Significance of Function Point Analysis

References