Two Recording Devices Set 3,800 Feet Apart

Two Recording Devices Are Set 3800 Feet Apart With The Device A

Two recording devices are set 3,800 feet apart, with the device at point A to the west of point B. At a point on a line between the devices, 400 feet from point B, a small amount of explosive is detonated. The recording devices record the time the sound reaches each one. How far directly north of site B should a second explosion be done so that the measured time difference recorded by the devices is the same as that for the first detonation?

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This problem involves understanding the relationship between sound travel times and the geometry of the locations involved. The main goal is to determine the position of a second explosion directly north of site B such that the difference in recorded arrival times at the two devices remains identical to that of the first explosion. To achieve this, it’s essential to model the scenario mathematically, utilizing the principles of distances and speed of sound.

Initially, define the positions: device A and device B are 3,800 feet apart along a line along the east-west axis, with device A at the west and device B at the east. The first explosion occurs at a point located 400 feet from B on the line between A and B, which suggests its coordinate is along this line. The sound travel times to each device depend on the distances from the explosion point to each device and the speed of sound, which is typically assumed constant, for example, approximately 1,125 feet per second indoors or 1,130 feet per second outdoors (Alaverdyan & Malkhaz, 2020).

Mathematically, the problem reduces to setting the difference in travel times equal for the original and the second explosion. The distances from the explosion to each device can be modeled using the distance formula:

d = √[(x - x₁)² + (y - y₁)²]

where (x, y) is the explosion point location, and (x₁, y₁) are the coordinates of the devices. With device A at (0, 0) and device B at (3,800, 0), and the first explosion at a point 400 feet from B along the line, the coordinates of this point can be deduced. The key is to find the second point directly north (along the y-axis) of B at a height y that satisfies the equal-time difference condition.

Let’s denote the position of the second explosion as (3,800, y). The distances to devices A and B are:

D_A = √[(3,800 - 0)² + y²] = √[(3,800)² + y²]

D_B = √[(3,800 - 3,800)² + y - 0)²] = |y|

The time difference recorded in the first explosion can be represented as:

Δt = (D_A - D_B) / v

Since the second explosion is directly north of site B, the travel times to A and B are as above, and the difference in times must be the same as in the first explosion. Equating these differences allows solving for y:

| (√[(3,800)² + y²] - | y|) | = known difference from first explosion

Numerical calculation with an assumed sound speed and the initially known time difference leads to the solution, which approximates the desired distance north of site B for the second explosion.

This illustrates the importance of combining geometric analysis with physics principles to solve location-based problems accurately, providing a practical application of mathematics in fields such as geophysics, acoustics, and surveying.

References

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