Use IMDb Ensures Correct Database Is Active 342152
Use Imdb Ensures Correct Database Is Activegoprint Repl
Use Imdb Ensures Correct Database Is Activegoprint Repl
USE IMDB -- ensures correct database is active GO PRINT '|---' + REPLICATE('+----',15) + '|' PRINT 'Read the questions below and insert your queries where prompted. When you are finished, you should be able to run the file as a script to execute all answers sequentially (without errors!)' + CHAR(10) PRINT 'Queries should be well-formatted. SQL is not case-sensitive, but it is good form to capitalize keywords and table names; you should also put each projected column on its own line and use indentation for neatness. Example: SELECT Name, CustomerID FROM CUSTOMER WHERE CustomerID
Paper For Above instruction
Introduction
This paper provides detailed SQL queries addressing a series of analytical questions based on the IMDB database schema. The queries are designed to extract specific insights about individuals, shows, genres, professions, and ratings, demonstrating proficient use of SQL techniques such as joins, subqueries, common table expressions, aggregations, window functions, and conditional logic.
Question 1: Birth Year and Show Directors
The first query retrieves the names and birth years of individuals born after 1980 who have directed at least one show and are deceased (deathYear is not null). It joins the name_basics table with title_directors to filter for directors, then filters on birth year and death status. The results are formatted with the primaryName as a 25-character wide string and sorted in descending order by birth year, ensuring the most recent are listed first.
SELECT
LEFT(n.primaryName, 25) AS Name,
n.birthYear
FROM
name_basics n
JOIN
title_directors td ON n.nconst = td.nconst
WHERE
n.birthYear > 1980
AND n.deathYear IS NOT NULL
ORDER BY
n.birthYear DESC;
Question 2: Genres of Highly Extended TV Shows
This query identifies all genres associated with TV episodes that have at least 200 episodes. It filters title_basics for titleType equal to 'tvEpisode'. It then joins with title_episode to find episodes with episodeNumber of 200, and cross-references with title_genres to obtain genre information. The distinct genres are listed, formatted to 15 characters, sorted alphabetically.
SELECT DISTINCT
LEFT(g.genre, 15) AS Genre
FROM
title_basics b
JOIN
title_episode e ON b.tconst = e.tconst
JOIN
title_genres g ON b.tconst = g.tconst
WHERE
b.titleType = 'tvEpisode'
AND e.episodeNumber = 200
ORDER BY
Genre;
Question 3: Identifying the Worst Shows
The third query employs a Common Table Expression (CTE) named BADSHOWS, representing shows with an average rating of 1. It joins title_basics with title_ratings on the tconst key. The main query groups by titleType to count the number of such poorly rated shows per type, ordering in descending order by the count.
WITH BADSHOWS AS (
SELECT
b.tconst,
b.title,
b.titleType,
b.startYear
FROM
title_basics b
JOIN
title_ratings r ON b.tconst = r.tconst
WHERE
r.averageRating = 1
)
SELECT
b.titleType,
COUNT(*) AS TOTAL_BAD_SHOWS
FROM
BADSHOWS b
GROUP BY
b.titleType
ORDER BY
TOTAL_BAD_SHOWS DESC;
Question 4: Least Popular Professions
This query counts the number of people associated with each profession in name_profession. It filters for professions with fewer than 1,000 individuals, highlighting the niche roles. The results display the profession name and count, formatted for clarity.
SELECT
profession,
COUNT(*) AS Total_People
FROM
name_profession
GROUP BY
profession
HAVING
COUNT(*)
Question 5: Names of People in Niche Professions
Building upon the previous query, this query retrieves the primary names of individuals belonging to professions with fewer than 1,000 members. It uses the previous counting as a subquery to filter people by their profession. Results are ordered alphabetically by name for easy reference.
SELECT
LEFT(n.primaryName, 25) AS Name,
p.profession
FROM
name_basics n
JOIN
name_profession p ON n.nconst = p.nconst
WHERE
p.profession IN (
SELECT profession
FROM (
SELECT
profession,
COUNT(*) AS cnt
FROM
name_profession
GROUP BY
profession
HAVING COUNT(*)
) sub
)
ORDER BY
n.primaryName DESC;
Question 6: Prolific Writers
This query identifies writers who have authored between 5,000 and 10,000 titles. It joins name_basics with title_writers on nconst, counts the titles per person, and filters within the specified range. Results are sorted in descending order by primaryName.
SELECT
LEFT(n.primaryName, 25) AS Name,
COUNT(*) AS Titles_Written
FROM
name_basics n
JOIN
title_writers tw ON n.nconst = tw.nconst
GROUP BY
n.nconst, n.primaryName
HAVING
COUNT(*) BETWEEN 5000 AND 10000
ORDER BY
n.primaryName DESC;
Question 7: Actors with Repeated Roles in "Battlestar Galactica"
This query finds actors who played the same character more than once in the "Battlestar Galactica" series. It joins name_basics with title_principals, filters for tconst entries corresponding to the series, groups by actor and character, and filters for counts greater than 1. The results are ordered by actor name.
SELECT
LEFT(n.primaryName, 25) AS Name,
p.characters,
COUNT(*) AS RoleCount
FROM
name_basics n
JOIN
title_principals p ON n.nconst = p.nconst
WHERE
p.tconst IN (
SELECT t.tconst
FROM title_basics t
WHERE t.primaryTitle = 'Battlestar Galactica'
AND t.titleType = 'tvSeries'
)
GROUP BY
n.nconst,
n.primaryName,
p.characters
HAVING
COUNT(*) > 1
ORDER BY
n.primaryName ASC;
Question 8: Directors of Top-Rated Shows
This query identifies individuals who have directed more than five shows with a perfect rating of 10. It joins name_basics, title_principals, title_ratings, and title_basics. It filters for shows with averageRating of 10, then groups by director, counting their total such shows. Only those with more than five are included.
SELECT
LEFT(n.primaryName, 25) AS Name,
COUNT(*) AS TopRatedShowsCount
FROM
name_basics n
JOIN
title_principals p ON n.nconst = p.nconst
JOIN
title_ratings r ON p.tconst = r.tconst
JOIN
title_basics b ON p.tconst = b.tconst
WHERE
p.job = 'director'
AND r.averageRating = 10
GROUP BY
n.nconst, n.primaryName
HAVING
COUNT(*) > 5
ORDER BY
TopRatedShowsCount DESC;
Question 9: Details of 1982 TV Specials
This query lists TV specials from 1982, displaying their titles and runtime minutes. If the runtime is NULL, it substitutes zero. Sorted in descending order by runtime, it helps identify the longest specials of that year.
SELECT
b.primaryTitle,
COALESCE(b.runtimeMinutes, 0) AS RuntimeMinutes
FROM
title_basics b
WHERE
b.titleType = 'tvSpecial'
AND b.startYear = 1982
ORDER BY
RuntimeMinutes DESC;
Question 10: Early Movies with Ratings and Ranks
This query retrieves movies from 1913 with known runtime and average ratings. It uses DENSE_RANK() to rank movies based on rating and runtime, assigning RATINGRANK and LENGTHRANK. The results are ordered alphabetically by title, facilitating analysis of their relative quality and length.
WITH RatingsAndLengths AS (
SELECT
b.primaryTitle,
r.averageRating,
DENSE_RANK() OVER (ORDER BY r.averageRating ASC) AS RATINGRANK,
DENSE_RANK() OVER (ORDER BY b.runtimeMinutes ASC) AS LENGTHRANK
FROM
title_basics b
JOIN
title_ratings r ON b.tconst = r.tconst
WHERE
b.startYear = 1913
AND b.titleType = 'movie'
AND b.runtimeMinutes IS NOT NULL
)
SELECT
primaryTitle,
averageRating,
RATINGRANK,
LENGTHRANK
FROM
RatingsAndLengths
ORDER BY
primaryTitle;
Conclusion
This compilation of SQL queries demonstrates a comprehensive approach to extracting varied insights from the IMDB database schema. Using a blend of joins, subqueries, CTEs, and window functions, the queries serve as effective templates for database analysis related to film and television data. Proper formatting and clear logic ensure readability and facilitate further customization or expansion.
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