Use The Given Conditions To Write An

Use The Given Conditions To Write An

Write equations for lines in point-slope form based on given conditions, including slopes and points through which the lines pass. Determine whether given relations are functions by examining their coordinate pairs. Calculate slopes of lines passing through specified points. Evaluate functions at given values of the independent variable. Determine whether equations define y as a function of x, and whether relations are functions.

Paper For Above instruction

Solving linear equations and determining functional relationships are fundamental skills in algebra. This paper discusses techniques for constructing equations of lines in point-slope form, analyzing whether relations are functions, calculating slopes, and evaluating functions at specific points.

Constructing Equations of Lines in Point-Slope Form

The point-slope form of a line's equation is expressed as y - y1 = m(x - x1), where m is the slope, and (x1, y1) is a point on the line. Provided with the slope and a point, this formula facilitates writing the equation directly.

For example, if the slope is 4 and the line passes through (-3, 7), the equation in point-slope form is:

y - 7 = 4(x + 3)

This corresponds to option C. Similarly, if the slope is known and the point is (8, 7), the equation becomes y - 7 = m(x - 8).

Analyzing Relations for Functionality

A relation is a set of ordered pairs. To determine if a relation is a function, one checks if each input (x-value) maps to exactly one output (y-value). For instance, the relation {(-2, -7), (3, -5), (6, -4), (9, -6), (10, -1)} assigns a unique y for each x, thus it is a function.

Conversely, a relation like {(-6, -9), (-2, 1), (1, -1), (7, -7)} also assigns single y-values for each x-value, making it a function as well, provided no x-value repeats with different y-values.

In the case of the relation {(1, -3), (1, 1), (6, -8), (9, -3), (11, -3)}, the x-value 1 maps to two different y-values (-3 and 1), so this relation is not a function.

Calculating Slopes of Lines

The slope (m) of a line passing through two points (x1, y1) and (x2, y2) is calculated as:

m = (y2 - y1) / (x2 - x1)

For example, for points (-8, 8) and (-5, 2):

m = (2 - 8) / (-5 + 8) = (-6) / 3 = -2

Similarly, for points (-2, -6) and (-9, -17):

m = (-17 + 6) / (-9 + 2) = (-11) / (-7) = 11/7

When the x-values are the same, such as points (-7, 6) and (-7, -9), the slope is undefined because division by zero occurs.

Evaluating Functions at Specific Values

To evaluate a function f(x) at a particular value, substitute that value into the function expression and simplify.

For instance, given f(x) = 4x2 + 5x - 6, and asked to compute f(x - 1):

f(x - 1) = 4(x - 1)2 + 5(x - 1) - 6

Expanding:

f(x - 1) = 4(x2 - 2x + 1) + 5x - 5 - 6 = 4x2 - 8x + 4 + 5x - 11 = 4x2 - 3x - 7

This simplifies to option A. Such evaluations are essential for understanding the behavior of functions at specific points.

Determining if Equations Define y as a Function of x

An equation defines y as a function of x if for each x, there is exactly one y. For example, the equation x2 + y2 = 1 represents a circle. Since solving for y yields y = ±√(1 - x2), it does not define y as a function of x because each x in (-1, 1) corresponds to two y-values (positive and negative). Therefore, y is not a function of x for this circle.

Conversely, in a linear equation like x + y = 9, solving for y gives y = 9 - x, which passes the vertical line test, confirming y is a function of x.

Conclusion

Mastery of these concepts enables students to interpret and construct lines and relations, evaluate functions, and determine the nature of mathematical relationships. These skills are foundational in higher mathematics and critical for problem-solving across numerous applications in science, engineering, and analytics.

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