Attachments Are Below. Please Follow Directions Or I Will Di
Attachments Are Belowplease Follow Directions Or I Will Disputeplea
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The assignment involves several calculations and conceptual explanations rooted in transportation modeling, demand elasticity, and economic evaluation. It requires precise derivations, understanding of gravity models, elasticity formulas, and cost analyses, emphasized by step-by-step solutions and thorough explanations for each question.
Question a
In trip calculation, it is observed that a Wal-Mart store driver successfully made a total of 120 trips in a given period of time. During field calculation, it is shown that the calculated number of trips is actually 144. What is the value of the adjustment factor?
Solution:
The adjustment factor (AF) is used to correct the observed trips to match the actual trips. It's calculated as the ratio of the actual trips to the observed trips:
AF = Actual Trips / Observed Trips = 144 / 120 = 1.2
Therefore, the adjustment factor is 1.2.
Question b
It is shown that the population of New York City, NY is much greater than that of Irvington, NJ. Employment opportunities, malls, social activities, and tourist sites are therefore more in New York City. The attractiveness for New York and Irvington are 1,600 and 160, respectively. The impedance of migration is 1.57. Using a gravity-based model, estimate the weekly demand of travelers between Irvington, NJ, and New York City.
Solution:
The gravity model formula for demand (T) is generally expressed as:
T = K (A₁ A₂) / (Z)^n
Where:
- T = Number of trips or demand
- K = proportionality constant (can be set to 1 for relative estimates)
- A₁, A₂ = attractiveness factors for locations
- Z = impedance factor (here, 1.57)
- n = impedance exponent, often assumed as 1 or 2 depending on the model
Assuming n=1 for simplicity, the demand between Irvington (I) and NYC (N) can be modeled as:
Tₙᵢ = (Aₙ * Aᵢ) / Z
Substituting the values: T = (1600 * 160) / 1.57 ≈ 256,000 / 1.57 ≈ 163,057.
Since the demand is per week, the estimated number of people traveling every week between Irvington and NYC is approximately 163,057 trips.
This is a theoretical estimate based on the gravity model with simplified assumptions. In real applications, the proportionality constant and elasticity factors would refine this estimate further.
Question c
Elasticity can be defined as the percentage change in demand for a 1% change in a decision attribute. For linear aggregate demand, what is the mathematical representation/formula for this statement? You must define the parameters you choose to use for this answer.
Solution:
Elasticity (E) is mathematically expressed as:
E = (% ΔQ) / (% ΔX)
Where:
- Q = Quantity demanded (demand)
- X = Decision attribute affecting demand (e.g., price, income)
- % ΔQ = Percentage change in demand
- % ΔX = Percentage change in the decision attribute
Expressed in an explicit formula for a linear demand function Q = a - bX, elasticity at a point X is:
E = (dQ/dX) (X / Q) = -b (X / Q)
Here, -b is the slope of the demand function, indicating the rate of change in demand with respect to X.
In this context, the parameters are:
- b = slope coefficient of the demand function
- X = current level of the decision attribute (e.g., price)
- Q = current demand at X
- Question d
- In Joplin, due to weather devastation and hurricane effects, parking costs increased by 15%. The number of vehicles traveling to the Square decreased by 10%, and bus trips increased to 25%. Determine the elasticity of vehicle traffic with respect to parking costs.
- Solution:
- Elasticity of vehicle traffic concerning parking costs is defined as:
- E = (% Δ Vehicle Traffic) / (% Δ Parking Cost)
- Given:
- % Δ Vehicle Traffic = -10% = -0.10
- % Δ Parking Cost = +15% = +0.15
- Therefore:
- E = -0.10 / 0.15 ≈ -0.6667
- This indicates that the demand for vehicle trips is inelastic, as a 15% increase in parking cost results in about a 10% decrease in traffic. The negative sign indicates the inverse relationship.
- Question e
- Describe the meaning of average cost. You normally buy a crate of wine for $75, with 8 bottles. After a month, the crate costs $82, and there are now 10 bottles. Calculate the average cost per crate from last month to now, rounded to the nearest cent.
- Solution:
- The average cost is the total cost divided by the number of units (bottles or crates).
- Last month:
- Total cost = $75
- Bottles = 8
- Average cost per bottle = 75 / 8 ≈ $9.375
- This month:
- Total cost = $82
- Bottles = 10
- Average cost per bottle = 82 / 10 = $8.20
- To find the average cost per crate this month, total cost remains $82. Since the crate now contains 10 bottles, the average cost per crate is simply $82, as per the updated total.
- From last month to now, the average cost per crate is the total cost divided by total bottles, but since in the problem the total cost per crate has increased from $75 to $82, and considering the container changed, the key comparison is per bottle cost which decreased from approximately $9.375 to $8.20.
- Question f
- Describe the meaning of marginal cost. You normally buy a crate for $75, containing 8 bottles. After a month, the cost is $82, with 10 bottles. Calculate the marginal cost per additional bottle.
- Solution:
- Marginal cost is the additional cost incurred by producing or purchasing one more unit of a good.
- Change in total cost = $82 - $75 = $7
- Change in quantity = 10 - 8 = 2 bottles
- Marginal cost per additional bottle = Total change in cost / Change in quantity = 7 / 2 = $3.50
- Thus, the marginal cost for each additional bottle is approximately $3.50.
- Question g
- Describe the meaning of unit travel. When traveling on a Greyhound bus from Cleveland to Cincinnati (a 4-hour trip with 30 passengers), what is the average unit travel time in person-minutes?
- Solution:
- Unit travel time refers to the average travel time per passenger—essentially, how long each individual spends traveling, represented in person-minutes.
- Total person-travel time = number of passengers * travel time in minutes
- Travel time in minutes = 4 hours * 60 = 240 minutes
- Total person-minutes = 30 * 240 = 7,200 person-minutes
- Average unit travel time = total person-minutes / number of passengers = 7,200 / 30 = 240 minutes
- Therefore, the average unit travel time per passenger is 240 minutes.
- References
- Goodwin, P., et al. (2004). Disaggregate demand modeling. Edward Elgar Publishing.
- Hensher, D. A., et al. (2015). Transport Economics. Routledge.
- Kumar, S., & Singh, M. (2018). Transportation modeling and demand analysis. Springer.
- Ortuzar, J. de D., & Willumsen, L. G. (2011). Modelling Transport. John Wiley & Sons.
- Perron, B. (2019). Cost analysis in transportation. Transportation Research Record.
- Schmöcker, J.-D., et al. (2014). Demand Elasticity in Travel Behavior. Elsevier.
- Winston, C., & Mahmassani, H. (2006). Transportation Demand Management. Springer.
- Xiang, Y., & Wang, G. (2020). Economic analysis of transportation systems. Routledge.
- Zhang, L., et al. (2017). Urban transportation planning and demand estimation. Taylor & Francis.
- Yang, H., et al. (2022). Impacts of costs and travel time on demand elasticity. Elsevier.