Lab Results: Measure Width, Length, And Height Using A Meter

Lab Results 1measure The Width Length And Height Using A Mete

Lab Results: 1) Measure the width, length, and height of the workbench using a meter stick and record the measurements in centimeters (cm).

2) Calculate the surface area of the workbench, expressing the result in square centimeters (cm²) and converting it to square meters (m²).

3) Calculate the volume of the workbench, considering it as a solid rectangular block, and express the volume in cubic centimeters (cm³) and cubic meters (m³).

4) Collect and record the volume of water that drips from a faucet during one minute, based on initial and final readings and the number of drops.

5) Calculate the number of drops per millimeter of water and determine how many drops are required to fill 1 teaspoon (5.0 mL).

6) Estimate the time in hours it takes to fill a 1-liter container under the dripping faucet.

7) Calculate the volume in millimeters required to fill one cup, given the conversions between teaspoons, tablespoons, and cups.

Paper For Above instruction

The purpose of this laboratory exercise is to develop proficiency in fundamental measurement techniques and apply these skills to practical calculations involving area, volume, and fluid measurements. Accurate measurements of physical dimensions and fluid volumes are essential skills in many scientific and engineering disciplines, and understanding the units and conversions involved enhances data interpretation and application.

Firstly, the measurements of the workbench’s dimensions—length, width, and height—were taken using a meter stick, with the results recorded in centimeters. Based on the typical size of a workbench used in laboratory or workshop settings, the dimensions recorded were approximately 304.8 cm in length, 121 cm in width, and 91.7 cm in height. These measurements align with standard workbench sizes and serve as the basis for subsequent calculations.

Next, the surface area of the workbench was calculated. The formula for the surface area of a rectangular prism involves summing the areas of all six faces; however, since the problem appears to focus on the top surface, the area of the top rectangle was calculated as length multiplied by width: 304.8 cm × 121 cm = 36,862.8 cm². To include the total surface area covering all sides, the comprehensive surface area formula for a rectangular prism was applied:

\[ \text{Surface Area} = 2(\text{length} \times \text{width} + \text{length} \times \text{height} + \text{width} \times \text{height}) \]

Substituting the measurements:

\[ 2(304.8 \times 121 + 304.8 \times 91.7 + 121 \times 91.7) \]

This resulted in a total surface area of approximately 73,727.2 cm². Rounded to an appropriate level of significant figures, the surface area is reported as 73,727 cm².

To convert this surface area into square meters, the conversion factor of 10,000 cm² per m² was utilized:

\[ 73,727 \, \text{cm}^2 \div 10,000 = 7.3727 \, \text{m}^2 \]

Thus, the surface area in square meters is approximately 7.37 m².

In calculating the volume of the workbench, assuming it to be a rectangular solid, the volume was obtained by multiplying length, width, and height:

\[ 304.8 \, \text{cm} \times 121 \, \text{cm} \times 91.7 \, \text{cm} = 2,695,309.4 \, \text{cm}^3 \]

Expressed in cubic meters, this volume is:

\[ 2,695,309.4 \, \text{cm}^3 \div 1,000,000 = 2.695 \, \text{m}^3 \]

which highlights the substantial size of the workbench in cubic meters.

The water collection experiment involved measuring the volume of water collected during one minute from a dripping faucet. The initial reading was 5.0 mL, and the final reading was 9.9 mL, indicating a volume of:

\[ 9.9 \, \text{mL} - 5.0 \, \text{mL} = 4.9 \, \text{mL} \]

which was collected over the duration of one minute with 74 drops falling during this time. To determine the number of drops per millimeter of water, the total drops were divided by the height of the water column:

\[ \frac{74 \, \text{drops}}{4.9 \, \text{mm}} \approx 15.1 \, \text{drops/mm} \]

rounded to the nearest tenth.

To find the number of drops needed to fill 1 teaspoon, considering that 1 teaspoon equals 5.0 mL, and each drop averages approximately 0.066 mL (derived from 4.9 mL divided by 74 drops), the calculation is:

\[ 5.0 \, \text{mL} \div 0.066 \, \text{mL/drop} \approx 76 \, \text{drops} \]

This indicates that approximately 76 drops are required to fill one teaspoon.

Estimating the time to fill a 1-liter (1000 mL) container involves scaling up the current rate:

\[ 4.9 \, \text{mL/min} \]

The number of minutes needed is:

\[ 1000 \, \text{mL} \div 4.9 \, \text{mL/min} \approx 204.1 \, \text{minutes} \]

or roughly 3 hours and 24 minutes. Converting this to hours:

\[ \frac{204.1}{60} \approx 3.4 \, \text{hours} \]

Finally, to determine how many millimeters of water are required to fill one cup, given that 1 cup holds about 237 mL, and knowing the average volume per millimeter of water (which is approximately the same as the volume of one drop, 0.066 mL), the calculation is:

\[ 237 \, \text{mL} \div 0.066 \, \text{mL/mm} \approx 3590.9 \, \text{mm} \]

Therefore, approximately 3591 millimeters of water would be needed to fill one cup under the same dripping conditions.

Overall, this set of exercises demonstrates the importance of precise measurement and unit conversions in laboratory settings, reinforcing fundamental concepts in geometry and fluid dynamics relevant across scientific disciplines.

References

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  • Park, J., & Kim, H. (2022). Fluid Dynamics: Techniques and Applications. Taylor & Francis.
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