Question 41 Exercise 40: Are You Visiting The Rainforest?

Question 41exercise 40ayou Are Visiting Therainforest But Unfortuna

You are visiting the rainforest, but unfortunately your insect repellent has run out. As a result, at each second, a mosquito lands on your neck with probability 0.5. If a mosquito lands, it will bite you with probability 0.2, and it will never bother you with probability 0.8, independently of other mosquitoes. What is the probability of being bitten for the first time in the 5th second?

Tackle this problem by carefully analyzing the sequence of events each second: no mosquito lands or mosquitoes land but do not bite, and finally, a mosquito bites for the first time at the 5th second. Use the laws of probability, accounting for the independence and conditional probabilities, to compute the likelihood that the first bite occurs precisely at the fifth second.

Paper For Above instruction

The scenario presents a classic problem involving compound probability events over discrete time intervals, specifically focusing on the probability of the first event occurrence—in this case, the first mosquito bite—at a specified second. To compute the probability that the first bite happens exactly at the fifth second, it is necessary to consider the sequence of events that occur at each second leading up to this point.

Initially, note that at each second, the probability that a mosquito lands is 0.5, and if it lands, it bites with probability 0.2, and does not bite with probability 0.8. Conversely, if no mosquito lands, then no bite is possible during that second. Importantly, the events at each second are independent, allowing us to multiply the respective probabilities for different seconds.

The detailed process involves three key stages at each second:

  1. Whether a mosquito lands (probability 0.5) or not (probability 0.5).
  2. If a mosquito lands, whether it bites (probability 0.2) or not (probability 0.8).

For the first occurrence of a bite at the fifth second, the following conditions must be met:

  • No bite occurs during the first four seconds, which encompasses all possible combinations of landing and biting events that do not lead to a bite.
  • A bite occurs precisely at the fifth second.

Expressed mathematically, the probability that no bite occurs in a given second is the sum of:

  • The probability no mosquito lands (0.5), and thus no bite is possible, which is 0.5.
  • The probability a mosquito lands (0.5), but it does not bite (0.8), totaling 0.4.

Together, the probability of no bite in one second is 0.5 + (0.5 * 0.8) = 0.5 + 0.4 = 0.9.

Similarly, the probability that a bite occurs in a second is the probability a mosquito lands and bites, i.e., 0.5 * 0.2 = 0.1.

To find the probability that the first bite occurs exactly at the fifth second, we need four consecutive seconds of no bite followed by a second with a bite:

P(first bite at second 5) = (Probability no bite in seconds 1-4) × (Probability bite at second 5)

= (0.9)^4 × 0.1

Calculating the numerical value:

(0.9)^4 = 0.6561

Thus, P(first bite at second 5) = 0.6561 × 0.1 = 0.06561

Therefore, the probability of being bitten for the first time exactly at the 5th second is approximately 6.561%.

This approach effectively models the problem using Bernoulli trials and the geometric probability distribution, where the "success" is the first bite occurring at the specified time, considering the independent nature of the events at each second and the combined probabilities of landing and biting.

References

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