Regular Price Of A Suit Is $99; It’s On Sale.

Question

The regular price of a suit is $99. The suit is on sale for 33 1/3% off. Find the sale price. 2. Dara borrowed $3000. She was charged at 15% per year. Find the interest for one year. 3. Joe paid $100 interest on money he borrowed for one year. The rate of the interest was 10%. How much money did her borrow? 4.The cost of a house increased 12% in one year. The original cost was $50,000. Find the cost one year later. 5.The sale price of a pair of shoes is $21. This is 70% of the regular price. Find the regular price. 6.A bicycle is advertised for a sale at 20% discount. The regular price is $150. Find the sale price.

Dr. Jack HW Helper · Accepted Answer

This paper addresses six distinct mathematical problems involving percentages, interest calculations, and basic algebra. Each problem will be solved step-by-step, demonstrating all necessary calculations and reasoning to arrive at the solutions. Problem 1: Finding the Sale Price of a Suit on Discount The original price of the suit is $99. It is offered at a 33 1/3% discount. First, convert the percentage discount to a decimal: $$ 33 \frac{1}{3}\% = \frac{100}{3}\% \approx 33.3333\% $$ which as a decimal is: $$ \frac{33.3333}{100} = 0.333333 $$ The amount of discount is then: $$ \text{Discount amount} = \text{Original price} \times \text{Discount rate} = \$99 \times 0.333333 \approx \$33 $$ Subtracting the discount from the original price yields the sale price: $$ \$99 - \$33 = \$66 $$ Therefore, the sale price of the suit is approximately \$66. Problem 2: Calculating the Interest on a Borrowed Amount Dara borrowed \$3000 at an annual interest rate of 15%. To find the interest for one year, use the simple interest formula: $$ \text{Interest} = \text{Principal} \times \text{Rate} \times \text{Time} $$ where the rate is expressed as a decimal and time in years is 1: $$ \text{Interest} = \$3000 \times 0.15 \times 1 = \$450 $$ Thus, Dara owes \$450 in interest after one year. Problem 3: Determining the Borrowed Amount from Interest Paid Joe paid \$100 interest for one year at an interest rate of 10%. The simple interest formula rearranged to find the principal is: $$ \text{Principal} = \frac{\text{Interest}}{\text{Rate} \times \text{Time}} $$ Plugging in the values: $$ \text{Principal} = \frac{\$100}{0.10 \times 1} = \frac{\$100}{0.10} = \$1000 $$ Hence, Joe borrowed \$1000. Problem 4: Computing the New Cost of a House After Price Increase The original cost of the house was \$50,000. It increased by 12%, which means the new cost is: $$ \text{New cost} = \text{Original cost} \times (1 + \text{Percentage increase}) $$ Express the percentage increase as a decimal: \[ 12\% =

Regular Price Of A Suit Is $99; It’s On Sale.

Paper For Above instruction

Problem 1: Finding the Sale Price of a Suit on Discount

Problem 2: Calculating the Interest on a Borrowed Amount

Problem 3: Determining the Borrowed Amount from Interest Paid

Problem 4: Computing the New Cost of a House After Price Increase

Problem 5: Finding the Regular Price of Shoes from Sale Price and Discount Percentage

Problem 6: Calculating the Sale Price of a Bicycle after Discount

Conclusion

References