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Given the detailed assignment prompts, the core tasks involve conducting hypothesis tests based on sample data, significance levels, and specified parameters. The focus includes identifying the type of test (one-tailed or two-tailed), formulating hypotheses, calculating test statistics, decision rules, p-values, and interpreting the results in the context of the research questions.
Below is an academically structured response addressing these hypothesis testing scenarios, incorporating relevant statistical principles, calculations, and interpretations with credible references.
Paper For Above instruction
Introduction
Hypothesis testing is a fundamental statistical method used to make inferences about population parameters based on sample data. It allows researchers to evaluate claims or assumptions regarding a population, using specified significance levels to decide whether to accept or reject null hypotheses. This paper explores multiple hypothesis testing scenarios involving means and proportions, illustrating the practical application of inferential statistics to real-world data.
Scenario 1: Testing the Population Mean with Known Standard Deviation
The first scenario involves a sample of 47 observations from a normally distributed population, with a sample mean of 31 and a population standard deviation of 4. The hypothesis test aims to determine if the population mean exceeds 30 at a 0.05 significance level. Since the population standard deviation is known, a z-test is appropriate. The hypotheses are set as H0: μ ≤ 30 and H1: μ > 30, indicating a one-tailed test in the right direction.
The decision rule involves calculating the critical z-value for α = 0.05 in a one-tailed test, which is approximately 1.645. If the computed test statistic exceeds this critical value, H0 will be rejected. The test statistic is calculated as:
z = (x̄ - μ₀) / (σ / √n) = (31 - 30) / (4 / √47) ≈ 1.91
Given that z = 1.91 > 1.645, we reject H0, suggesting significant evidence that the true population mean exceeds 30. The p-value corresponding to z=1.91 is approximately 0.0281, reinforcing this conclusion.
Scenario 2: Testing Mean Daily Tips for a Server
In the second scenario, Beth Brigden's tips are analyzed to assess if her average tips are more than $86. The sample size is 48 days, with a mean of $87.07 and a population standard deviation of $3.81. The hypotheses are H0: μ ≤ 86 and H1: μ > 86, making this a one-tailed test. The critical z-value at α=0.02 is approximately 2.054.
The test statistic is:
z = (87.07 - 86) / (3.81 / √48) ≈ 2.94
Since 2.94 > 2.054, H0 is rejected, indicating that Beth's tips are statistically higher than $86 at the 2% significance level. The p-value for z=2.94 is approximately 0.0016, supporting this conclusion.
Scenario 3: Testing the Average Number of Sales Calls
The third case involves assessing whether sales representatives make more than 37 calls per week. The sample includes 41 representatives with a mean of 40 calls and a standard deviation of 5.6. The hypotheses are H0: μ ≤ 37 and H1: μ > 37, resulting in a one-tailed test. Since the standard deviation of the population is unknown, a t-test is suitable.
The calculated t-statistic is:
t = (40 - 37) / (5.6 / √41) ≈ 3.33
At α=0.025 and degrees of freedom (df)=40, the critical t-value is approximately 2.021. Because 3.33 > 2.021, H0 is rejected, indicating that sales calls are significantly more than 37 on average.
Scenario 4: Comparing Family Income to Reported Mean
This scenario investigates whether a small sample suggests a deviation from the reported mean family income of $27,540 among Mexican migrants. The sample size is 19, with a mean of $28,956 and a sample standard deviation of $10,250. The hypotheses are H0: μ = 27,540 and H1: μ ≠ 27,540, requiring a two-tailed t-test at the 0.01 significance level.
The test statistic is:
t = (28,956 - 27,540) / (10,250 / √19) ≈ 0.60
Critical t-values for df=18 at α=0.01 (two-tailed) are approximately ±2.878. Since |0.60|
Scenario 5: Testing the Population Mean Against a Threshold
Here, the goal is to test whether the mean is less than 220. The sample size is 64, with a mean of 215 and a population standard deviation of 15. The hypotheses are H0: μ ≥ 220 and H1: μ
The test statistic is:
z = (215 - 220) / (15 / √64) = -5 / (15/8) ≈ -2.67
Since -2.67
Scenario 6: Testing If the Mean Exceeds a Value
For this test, with a sample mean of 12, sample standard deviation of 3, sample size of 10, and hypotheses H0: μ ≤ 10 and H1: μ > 10, the significance level is 0.05. Because the population standard deviation is unknown, a t-test with df=9 is used.
The test statistic is:
t = (12 - 10) / (3 / √10) ≈ 2.108
The critical t-value at α=0.05 and df=9 is approximately 1.833. Since 2.108 > 1.833, H0 is rejected, providing evidence that the mean exceeds 10.
Scenario 7: Two-Tailed Test for Population Mean
This scenario tests whether the population mean differs from 400, with a sample mean of 407, standard deviation of 6, and sample size of 12 at 0.01 significance. The hypotheses are H0: μ = 400 and H1: μ ≠ 400.
The test statistic is:
t = (407 - 400) / (6 / √12) ≈ 4.082
Degrees of freedom = 11; critical t-values for a two-tailed test at α=0.01 are approximately ±3.106. Because 4.082 > 3.106, H0 is rejected, indicating a significant difference from 400.
Conclusion
The above analyses demonstrate how hypothesis testing facilitates informed decision-making based on sample data. Whether the context involves means or proportions, knowing the correct test type, calculating test statistics accurately, and interpreting results in light of significance levels are essential skills in statistical analysis.
References
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