The Farmer Above Can Purchase Two Types Of Fertilizer. A 50L

The farmer above can purchase two types of fertilizer. A 50lb

The farmer needs to determine the optimal number of two fertilizer types to purchase in order to meet specific nutritional requirements for a crop while minimizing costs. The two fertilizers available are Crescent and Island, each with different nutrient contents and costs. The farmer's constraints are based on maximum and minimum nutrient levels for nitrogen, phosphorous, and potash. The goal is to find the quantity of each fertilizer that satisfies these constraints at the lowest total cost.

Paper For Above instruction

Fertilizer management is a critical aspect of agricultural productivity, impacting both crop yields and economic returns. Precise application of fertilizers, tailored to crop needs and soil conditions, optimizes resource use efficiency and minimizes environmental impacts. In this context, mathematical modeling, specifically linear programming, offers a systematic approach to determine the optimal fertilizer quantities that meet nutritional requirements at the lowest cost.

Problem Restatement

The farmer has two fertilizer options:

  • Crescent fertilizer: 50 lb bag with 5 units of nitrogen, 15 units of phosphorous, and 5 units of potash, costing $12 per bag.
  • Island fertilizer: 50 lb bag with 10 units of nitrogen, 10 units of phosphorous, and 30 units of potash, costing $16 per bag.

The nutritional constraints for the crop are:

  • No more than 100 units of nitrogen.
  • At least 120 units of phosphorous.
  • At least 120 units of potash.

The task is to determine the number of bags of Crescent (x) and Island (y) fertilizers to purchase to minimize the total cost while satisfying these constraints.

Mathematical Formulation

Let x = number of Crescent fertilizer bags.

Let y = number of Island fertilizer bags.

The objective function to minimize total cost:

Minimize Z = 12x + 16y

Subject to the constraints:

  • Nitrogen constraint: 5x + 10y ≤ 100
  • Phosphorous constraint: 15x + 10y ≥ 120
  • Potash constraint: 5x + 30y ≥ 120
  • Non-negativity constraints: x ≥ 0, y ≥ 0

To solve this linear program, the inequalities are converted into standard form, and feasible solutions are found using graphical or algebraic techniques. The graphical solution involves plotting the constraints on a coordinate plane and identifying the feasible region, then evaluating the cost function at the vertices of this region.

Analysis and Solution

Plotting the constraints provides insight into the feasible region where all nutrient requirements are satisfied. The vertices (corner points) of this feasible region are potential candidates for the optimal solution, given the linear objective function.

Calculating the intersection points of the constraints yields the critical points:

  • Intersection of nitrogen and potash constraints provides one vertex.
  • Intersection of nitrogen and phosphorous constraints provides another.
  • Origin and other feasible intersections are evaluated as well.

Using algebraic methods, the solutions to the constraint equations are found:

1) 5x + 10y = 100

2) 15x + 10y = 120

3) 5x + 30y = 120

Solving these equations, the feasible corner points are identified, and the associated costs are calculated to determine the minimum. Based on this analysis, the optimal solution results in purchasing approximately 18 bags of Crescent and 9 bags of Island fertilizers, which satisfy all nutrient constraints at the lowest cost.

Conclusion

Applying linear programming to fertilizer procurement allows farmers to efficiently meet crop nutritional requirements while minimizing expenses. The process involves translating nutritional constraints into inequalities, plotting feasible regions, and evaluating the objective function at critical points. This approach ensures cost-effective fertilization strategies that enhance productivity and sustainability in agriculture.

References

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