We Are The Monroe Family; We Own A Used Car Lot And Sell Use

Question

We Are The Monroe Family We Own A Used Car Lot And Sell Used Cars To We are the Monroe family. We own a used car lot and sell used cars to lots of people. My dad called me in and told me if I could solve a math problem about the car lot, I would earn a reward. My dad is always trying to prepare me for the real world. He also said I should have my sister Monica help me find the solution and I could even have you help me. So I put on your thinking caps. Our lot has a total of 120 cars. They come in colors shown on the graph: black, blue, gray, green, orange, red, tan, yellow. Tan cars are half the number of red cars. Blue cars are equal to gray cars. Gray cars are equal to the number of red cars. Black cars are five fewer than red cars. Orange cars are five more than tan cars. Green cars are five more than red cars. The number of red cars is between 19 and 21. Additionally, the number of orange cars plus yellow cars must be considered.

Dr. Jack HW Helper · Accepted Answer

The problem involves analyzing the distribution of cars of different colors on a used car lot with specific relationships among the numbers in each category. This type of problem is suitable for solving with algebra, where variables represent the unknown quantities, and the given relationships provide equations to find these variables. First, we let R represent the number of red cars. According to the problem, R is between 19 and 21, so R is either 20 (since it's an integer, and the only integer between 19 and 21). We then use this value to find the number of cars in each other category: Tan cars = 1/2 of red cars = ½ R = ½ 20 = 10 cars. Gray cars = same as blue cars = same as red cars = R = 20 cars. Black cars = red cars minus 5 = 20 - 5 = 15 cars. Orange cars = tan cars minus 5 = 10 - 5 = 5 cars. Green cars = red cars plus 5 = 20 + 5 = 25 cars. Since the total number of cars is 120, let's verify the sum of these known quantities: Red: 20 Gray: 20 Blue: 20 (since gray equals blue) Tan: 10 Black: 15 Orange: 5 Green: 25 Adding these gives: 20 + 20 + 20 + 10 + 15 + 5 + 25 = 115 cars. However, the total must be 120, so we are missing 5 cars, which are yellow cars and possibly others not accounted for yet. Given that orange cars plus yellow cars are mentioned together, and the total is 120, the remaining cars (120 - 115 = 5) must be yellow cars or categorized accordingly. Therefore, yellow cars = 5, which completes the total: 115 + 5 = 120 cars. Now, the distribution is as follows: Red: 20 Gray: 20 Blue: 20 Tan: 10 Black: 15 Orange: 5 Green: 25 Yellow: 5 Some of the relationships in the problem, such as comparing orange and yellow cars, also hold true: orange (5) plus yellow (5) equals 10, which may be significant depending on further context. In conclusion, by applying algebraic relationships and considering the total number of cars, we can determine the approximate distribution of cars across the different colors in the lot, specifically confirming that there are 20 r

We Are The Monroe Family We Own A Used Car Lot And Sell Used Cars To

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