A Random Variable X Results From An Experiment In Which A Fa

A Random Variable X Results From An Experiment In Which A Fair 1

1. A random variable X results from an experiment in which a fair 6-sided die is rolled at the same time a fair coin is flipped. Specifically, X equals the sum of the number of dots showing on the die and the number of heads showing on the coin.

a) Determine all possible values of X and the probability of occurrence for each of these values (the pmf of X). Show your work or justify your answer.

b) Plot the cumulative distribution function (CDF) F(x) of X, clearly labeling all values on both axes.

c) Determine the mean of X, showing your work.

Paper For Above instruction

The experiment described involves rolling a fair six-sided die and flipping a fair coin simultaneously. The random variable X, defined as the sum of the die's outcome and the number of heads from the coin flip, can take various values based on the outcomes of both experiments. This analysis aims to determine the probability mass function (pmf), plot the cumulative distribution function (CDF), and calculate the mean of X.

Part A: Determining All Possible Values and Their Probabilities

Each outcome of the die can be represented by the numbers 1 through 6, each with probability 1/6, since the die is fair. The coin flip results in either 0 (tails) or 1 (heads), each with probability 1/2. The combined sample space consists of 12 outcomes, with each outcome's probability being the product of the individual probabilities: (1/6) for the die outcome and (1/2) for the coin result, totaling 1/12 per outcome.

The possible sums X are calculated as the sum of the die value (D) and the coin result (C). Since D ranges from 1 to 6 and C is either 0 or 1, the possible values of X are:

  • If C=0 (tails), X = D + 0 = D, possible values 1 through 6.
  • If C=1 (heads), X = D + 1, possible values 2 through 7.

Therefore, the possible values of X are 1, 2, 3, 4, 5, 6, and 7.

Now, calculate the probability for each value:

  • X=1: occurs only when die=1 and coin=tails: P=1/12.
  • X=2: can occur in two ways:
    • die=1, coin=heads: P=1/12
    • die=2, coin=tails: P=1/12

    Total: P=2/12=1/6.

  • X=3:
    • die=1, coin=tails: P=1/12
    • die=2, coin=heads: P=1/12
    • die=3, coin=tails: P=1/12

    Total: 3/12=1/4.

  • X=4:
    • die=1, coin=heads: P=1/12
    • die=2, coin=tails: P=1/12
    • die=3, coin=heads: P=1/12
    • die=4, coin=tails: P=1/12

    Total: 4/12=1/3.

  • X=5:
    • die=2, coin=heads: P=1/12
    • die=3, coin=tails: P=1/12
    • die=4, coin=heads: P=1/12
    • die=5, coin=tails: P=1/12

    Total: 4/12=1/3.

  • X=6:
    • die=3, coin=heads: P=1/12
    • die=4, coin= tails: P=1/12
    • die=5, coin=heads: P=1/12
    • die=6, coin=tails: P=1/12

    Total: 4/12=1/3.

  • X=7:
    • die=4, coin=heads: P=1/12
    • die=5, coin= tails: P=1/12
    • die=6, coin= head: P=1/12

    Total: 3/12=1/4.

In summary, the pmf is:

X Probability
11/12
21/6
31/4
41/3
51/3
61/3
71/4

Part B: Plotting the CDF F(x)

The cumulative distribution function (CDF) F(x) is obtained by summing the probabilities for all X values less than or equal to x. The step functions are as follows:

  • F(x)=0 for x
  • F(1)= P(X=1)=1/12
  • F(2)=F(1)+P(X=2)=1/12+1/6=1/12+2/12=3/12=1/4
  • F(3)=F(2)+P(X=3)=3/12+1/4=3/12+3/12=6/12=1/2
  • F(4)=F(3)+P(X=4)=6/12+1/3=6/12+4/12=10/12=5/6
  • F(5)=F(4)+P(X=5)=10/12+1/3=10/12+4/12=14/12>1, but since total probability is 1, F(5)=1
  • Similarly, for x≥7, F(x)=1

Graphically, F(x) is a step function increasing at each X value with the corresponding probabilities.

X-axis: values 1 through 7.

Y-axis: probabilities from 0 to 1.

All values explicitly labeled in the plot.

Part C: Calculating the Mean of X

The mean (expected value) of X is calculated as:

E[X] = Σ x * P(X=x)

Calculations:

  • E[X] = 1(1/12) + 2(1/6) + 3(1/4) + 4(1/3) + 5(1/3) + 6(1/3) + 7*(1/4)

Expressed with common denominators:

  • 1*(1/12) = 1/12
  • 2(1/6) = 2(2/12) = 4/12
  • 3(1/4) = 3(3/12) = 9/12
  • 4(1/3) = 4(4/12) = 16/12
  • 5*(1/3) = 20/12
  • 6*(1/3) = 24/12
  • 7(1/4) = 7(3/12) = 21/12

Summing up:

E[X] = (1 + 4 + 9 + 16 + 20 + 24 + 21)/12 = 95/12 ≈ 7.9167

Thus, the expected value of X is approximately 7.92.

Conclusion

This analysis provides a detailed characterization of the random variable X resulting from the combined experiment of rolling a die and flipping a coin. The pmf reveals the probabilities associated with each sum, which are useful for understanding the distribution's shape. The plotted CDF illustrates the cumulative probabilities up to each value, facilitating visualization of the distribution. The calculated mean offers insight into the average outcome of this combined process, which lies between the minimum and maximum possible sums.

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