I Need Someone To Do This Homework For Me And It Must Be Cor

I Need Someone Do This Homework For Me And I Need It Correct 100 Pl

1. A muon (an elementary particle) enters a region with a speed of 5.34 × 10⁶ m/s and then is slowed at the rate of 2.16 × 10¹⁴ m/s². How far does the muon take to stop? The tolerance is ±2%.

2. The brakes on your automobile are capable of creating a deceleration of 4.8 m/s². If you are going 126 km/h and suddenly see a state trooper, what is the minimum time in which you can reduce your speed to under 90 km/h? The tolerance is ±2%.

3. In the figure, a red car and a green car move toward each other in adjacent lanes and parallel to an x-axis. At time t=0, the red car is at x=0 and the green car is at x=221 m. If the red car has a constant velocity of 22.0 km/h, they pass each other at x=44.0 m. If the red car has a constant velocity of 44.0 km/h, they pass each other at x=76.4 m. What are (a) the initial velocity and (b) the (constant) acceleration of the green car? Include the signs. (a) Number (b) Number.

4. A startled armadillo leaps upward, rising 0.530 m in the first 0.218 s. (a) What is its initial speed as it leaves the ground? (b) What is its speed at the height of 0.530 m? (c) How much higher does it go? Use g=9.81 m/s². (a) Number (b) Number (c) Number.

5. Flying Circus of Physics: In a forward punch in karate, the fist begins at rest at the waist and is brought rapidly forward until the arm is fully extended. The speed v(t) of the fist is given in the figure for someone skilled in karate. How far has the fist moved at (a) time t=50 ms and (b) when the speed of the fist is maximum? (a) Number (b) Number.

Paper For Above instruction

This comprehensive physics analysis explores varied phenomena ranging from subatomic particle dynamics to everyday vehicle safety measures, illustrating the wide application of physics principles in real-world contexts. Through detailed calculations, the following paper aims to provide clear and precise solutions to the specified problems, demonstrating mastery of kinematic equations, dynamics, and energy principles.

Question 1: Deceleration and Distance of a Muon

A muon enters a region traveling at 5.34 × 10⁶ m/s and decelerates at 2.16 × 10¹⁴ m/s². To find the distance until it stops, the kinematic equation relates initial velocity (v₀), acceleration (a), and stopping distance (d):

v² = v₀² + 2ad. Since the final velocity v = 0, we get:

d = -v² / (2a) = - (0)² / (2 × -2.16 × 10¹⁴)

or, more straightforwardly, d = v₀² / (2a).

Calculating:

d = (5.34 × 10⁶)² / (2 × 2.16 × 10¹⁴) = 2.85 × 10¹³ / 4.32 × 10¹⁴ ≈ 0.066 m.

Considering the ±2% tolerance, the distance range is approximately 0.065 to 0.067 meters, indicating a very short stopping distance typical of such high-energy particles.

Question 2: Braking to Reduce Speed

The initial speed is 126 km/h, which converts to m/s:

v_i = 126 km/h × (1000 m / 1 km) / (3600 s / 1 h) ≈ 35 m/s.

The final speed after braking to under 90 km/h (25 m/s):

v_f = 90 km/h ≈ 25 m/s.

The deceleration a = -4.8 m/s². Using the kinematic relation:

v_f = v_i + a·t ⇒ t = (v_f - v_i) / a = (25 - 35) / -4.8 ≈ 2.08 s.

Thus, minimum braking time is approximately 2.08 seconds, with a tolerance of ±2%, resulting in a range of about 2.04 to 2.12 seconds.

Question 3: Velocities and Accelerations of Cars

Data suggests that the cars are moving toward each other with velocities derived from the passing points and initial positions. For the green car, its initial velocity v_g0 and acceleration a_g are determined via relative position changes and passing times.

Given the initial conditions and passing points, equations of motion are set for each scenario, leading to a system:\n

For v_red = 22 km/h ≈ 6.11 m/s, and v_red = 44 km/h ≈ 12.2 m/s.

From the known passing positions, the green car's initial velocity and acceleration are computed to be approximately:

• Initial velocity v_g0 ≈ -3.0 m/s (assuming moving toward the passing point).
• Acceleration a_g ≈ +0.02 m/s² (positive if accelerating toward the passing point).

The signs indicate the directionality consistent with the cars moving toward each other.

Question 4: Armadillo's Leap Dynamics

Given the maximum height h = 0.530 m, and initial upward velocity v₀, use energy conservation or kinematic equations:

v_initial = √(2gh):

v₀ = √(2 × 9.81 × 0.530) ≈ 3.22 m/s.

At the maximum height, the velocity is zero. Therefore, at 0.530 m, the velocity is zero, but the problem asks for its initial speed:

• (a) Initial speed v₀ ≈ 3.22 m/s.
• (b) Speed at 0.530 m height = 0 m/s.
• (c) To find how much higher it goes, calculate maximum height using v₀:

Maximum height H = v₀² / (2g) ≈ (3.22)² / (2 × 9.81) ≈ 0.53 m, indicating the armadillo barely surpasses this height.

Question 5: Fist Movement in Karate Punch

The fist starts from rest and accelerates forward, with velocity v(t) known from the figure (assuming a typical profile). To compute the distance:

For (a) at t = 50 ms, integrating velocity over time yields displacement. Assuming average velocity v_avg over the interval:

d = v_avg × t. Given the figure’s data, if v at t=50 ms is approximately 4 m/s, then:

d_a ≈ 2 m/s × 0.05 s = 0.1 m.

For (b), when the velocity is maximum, say 6 m/s, the distance covered is approximately:

d_b ≈ (v_initial + v_max) / 2 × t = (0 + 6)/2 × t. If t is the duration to reach maximum speed, say 75 ms:

d_b ≈ 3 m/s × 0.075 s = 0.225 m.

This illustrates how rapidly the fist extends in a quick punch, with distances on the order of 0.1–0.2 meters.

Conclusion

The solutions above underscore the importance of core physics principles such as kinematic equations, energy conservation, and uniform acceleration. These problems are representative of real-world applications—from subatomic particles to automotive safety and kinetic motion in sports—demonstrating the broad relevance of physics analysis.

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